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Search results
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Mathematics: Post your doubts here!
Really? I must have missed something.(im sure it would be something obvious ):p -
Mathematics: Post your doubts here!
y yup! The 7 marked one was especially tough! -
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Holy FLubber Nuggets math 12 was hard!!
you know i don't think we can discuss the paper right now. -
Mathematics: Post your doubts here!
i guess it was ok! Alhamdulillah! but i made a few silly mistakes that i wouldn't normally make. Major ones.Ugh. Yours? -
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Holy FLubber Nuggets math 12 was hard!!
i left it blank :(:cry: didn't get time to attempt it later on. -
Mathematics: Post your doubts here!
Messed up pretty bad!!!!:cry: btw can we discuss it today by evening -
Mathematics: Post your doubts here!
Me too. Although i hate stats, especially permuations and combinations.:( -
Mathematics: Post your doubts here!
Actually the curve cannot cut the x- axis at pi, tan is undefined for pi. Nor 2pi since they haven't asked for it. -
Mathematics: Post your doubts here!
I've got another doubt in the same paper... Q10 (iii)... I got the critical values= 0 and 64/9 but then what would be the inequality... i reckoned that since "a" in negative in -kx^2 + 3kx -16 i.e. -k, the graph would have an upward parabola, but it turned out to be wrong. -
Mathematics: Post your doubts here!
thnx! But i got it upto then. But, wasn't able to solve simultaneously. -
Mathematics: Post your doubts here!
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s12_qp_12.pdf anyone? please help. Q7b. -
Mathematics: Post your doubts here!
since g(x) = x-2 and hg = f replace the "g" part in "f" by x. You get h(x) = x^2 +3 -
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Mathematics: Post your doubts here!
You should remember that |r| < 1 for a convergant sequence In this question r = 1/3 tan^2 θ therefore, 1/3 tan^2 θ < 1 tan^2 θ < 3 tan θ < [sqrt]3 θ < π/3 -
Mathematics: Post your doubts here!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf There's a problem in 6(i) right? -
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Mathematics: Post your doubts here!
I think this will help: If (b^2-4ac) > 0 , the equation will have 2 roots. If (b^2-4ac) < 0 , the equation will have no roots. If (b^2-4ac) = 0 , the equation will have 1 root.