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  1. Maz

    Mathematics: Post your doubts here!

    Put in the values given i.e. x<=1 into g(x) you would get g(x) >= -9
  2. Maz

    Mathematics: Post your doubts here!

    AB = b -a = (k-1 , -k, 2k - 2) Unit vector = vecter/ magnitude Therefore, (k-1, -k, 2k-2)/[sqrt] (k-1)^2 + (-k)^2 + ((2k -2)^2 Since they have said that the vector AB is the unit vector, the magnitude would equal 1. Equate the magnitude you should get the answer.
  3. Maz

    Mathematics: Post your doubts here!

    anyone???
  4. Maz

    Mathematics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf 4(i) I'm not at my best today. herein, i got themethod from the ms but not why.
  5. Maz

    Mathematics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w12_qp_12.pdf 3(ii) Please! Thnx.
  6. Maz

    Mathematics: Post your doubts here!

    qwerty123123 gave you the correct answer, but if you are still confused as to how to go about it then here goes. What i do is substitue the whole sinx, sin(1/2x), or for that matter cosx or any other cos or sin function by 1 for the maximun value and -1 for the minimum value. I guess you can...
  7. Maz

    Thnx for the follow. And give my regards to my alter ego in the "parallel universe".

    Thnx for the follow. And give my regards to my alter ego in the "parallel universe".
  8. Maz

    Mathematics: Post your doubts here!

    If you put in the value of x, i.e. '0', in both dy/dx and the original equation you will get the gradient and coordinates of the y intercept. and so put those in, in y = mx +c
  9. Maz

    Mathematics: Post your doubts here!

    4/15(3(-1) +4)^(5/2) - 3(-1)^2 -8(-1) +c = 5 4/15 -3 +8 +c = 5 c = 5 -8 +3 -4/15 c = -4/15 There you have it!
  10. Maz

    Mathematics: Post your doubts here!

    find the equation from what?
  11. Maz

    Mathematics: Post your doubts here!

    Hope you remember that m1*m2 = -1 i.e. the products of two gradients is equal to -1 if the two lines are perpendicular.
  12. Maz

    Mathematics: Post your doubts here!

    Limits mean the the values of x between which the graph stretches. For instance if the dy/dx is given as = 3x^2, the integration of this will give us y=x^3. it is correct however dy/dx= 3x^2 can also be gotten from y=x^3+2 or =x^3+4, there are multiple answers therefore we add "+c". I hope that...
  13. Maz

    Mathematics: Post your doubts here!

    @GorgeousEyes 9i) if OAB is a straight line then OA is a part of OB, Therefore, by comparing the two vectors we can that OB is twice of OA p = 2 unit vector = each vector/ magnitude of vector = (2i+ j + k)/(2^2 +1 +1)[square root] =...
  14. Maz

    Mathematics: Post your doubts here!

    forgive me the uneven graph but actually the curve downwards is equal to the curve upwards
  15. Maz

    Mathematics: Post your doubts here!

    GorgeousEyes 8iii) Simple integration: After that put in the value of x = -1 and find "c" i guess you could do that. And sorry about the stupid drawing
  16. Maz

    Mathematics: Post your doubts here!

    I'll answer your questions one by one 6i) gf(x) = 1 f(x) = 1/2 x +1/6 n [take that n as pi please :D ] g(1/2 x + 1/6 n) = 1 cos ( 1/2 x + 1/6 n ) = 1 1/2 x + 1/6 n = cos-1( 1) 1/2 x + 1/6 n = 0 1/2 x = -1/6 n x = 2(- 1/6 n ) x = -n/3
  17. Maz

    Mathematics: Post your doubts here!

    Me? Sorry, I'm going to appear for my "AS" levels. i won't be able to solve 'A2" level questions.:confused:
  18. Maz

    Mathematics: Post your doubts here!

    June-12/12 7) Using the formula given first find the sum of the first 1 term. (sounds funny) Sn= 1^2 + 8(1) = 9 Then find of sum of the first two terms Sn= 2^2 + 8(2) = 20 subtract the two terms to get the second term 20-9 = 11 and then 11-9 = 2 is the...
  19. Maz

    Mathematics: Post your doubts here!

    falcon678 I'll try to answer the others later, InshaAllah
  20. Maz

    "Be like a tree, even if people throw a stone to harm you, drop a Fruit to Benefit them"

    "Be like a tree, even if people throw a stone to harm you, drop a Fruit to Benefit them"
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