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  1. M

    Physics 43!! How was it?? Expected GT anyone?

    Power i got 2.96x10^-3W, P=v square/R the resistance is just a straight line
  2. M

    Physics 43!! How was it?? Expected GT anyone?

    will they cut marks for that?^because i did the same thing
  3. M

    Physics 43!! How was it?? Expected GT anyone?

    not too easy, not too hard.. i hope i get at least an 80..skipped the medical aprt..damn never focused on that sub topic at all
  4. M

    Physics: Post your doubts here!

    May June 2004 question 6 paper 4 please..TT
  5. M

    Physics: Post your doubts here!

    peak voltages=+5 and -5 5+(-5) divide by 2 and its 0.
  6. M

    Physics: Post your doubts here!

    change in current=change in flux linkage. you need this to induce voltage in the core, so that the secondary current recieves the voltage/current as well.
  7. M

    Mathematics: Post your doubts here!

    _________ you do denominator|numerator , as the powers are the same on both sides
  8. M

    Mathematics: Post your doubts here!

    bump
  9. M

    Mathematics: Post your doubts here!

    what year is it? the equation at ii uses 2 theta, so its actually Rsin(2t-alpha), not just 1 theta
  10. M

    Mathematics: Post your doubts here!

    http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_s11_qp_33.pdf Also what is the proper way to do 7iii?
  11. M

    Mathematics: Post your doubts here!

    iii and iv, sorry
  12. M

    Mathematics: Post your doubts here!

    Guys, http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w08_qp_3.pdf number 10 please.
  13. M

    Mathematics Paper 3: Post your doubts!

    its ln(x)/sqrt(x), so its just x^-.5ln(x), you move the sqrt(x) up basically. its like x/y becomes xy^-1
  14. M

    Mathematics Paper 3: Post your doubts!

    you integrate x^-1/2 (ln x) by parts
  15. M

    Mathematics Paper 3: Post your doubts!

    Its 1/z, a fraction, so u multiply it with a conjugate, which is (1+cos2t) MINUS isin2t, which is z*/z(z*) since were only interested in the real part, you do (1+cos2t)/[(1+cos2t)+isin2t][(1+cos2t) - isin2t], apply trigo identities here, sin^2(2t)+cos^2(2t)=1 in the end youll get...
  16. M

    Mathematics: Post your doubts here!

    http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w09_qp_31.pdf 7 iv please. thanks in advance.
  17. M

    Mathematics: Post your doubts here!

    oh ok :P
  18. M

    Mathematics: Post your doubts here!

    the circle must pass the origin, as the radius is |u|
  19. M

    Mathematics: Post your doubts here!

    thanks a lot :)
  20. M

    Mathematics: Post your doubts here!

    http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_31.pdf number 7ii and iii. Anyone can help? thanks.
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