Mathematics: Post your doubts here!

[shanky631]

can someone plzz help me with this
http://www.mediafire.com/?8bbfh1r92a9luxf

shanky631
whitecorp
View attachment 17371

Which paper is this??

 

[Mattman]

the circle must pass the origin, as the radius is |u|

 

[Mattman]

Bro, the credit goes to whitecorp. So thank him.

oh ok

 

[Albert Einstein]

just attach a scan aor anything for the ans. as i jxt reached the ans, bt there is sumthing bothering .... if u will attach a help or sumthing it will be beneficial

No answer just have to show its for 2 marks only

 

[leadingguy]

No answer just have to show its for 2 marks only

that means I will surely get one nt sure ab the second will give another try soon

 

[Albert Einstein]

that means I will surely get one nt sure ab the second will give another try soon

okii

 

[leadingguy]

okii

It will really be a pleasure to assist Albert Einstein

 

[bamteck]

minato112 or whitecorp
http://www.xtremepapers.com/papers/...AS Level/Mathematics (9709)/9709_s05_qp_3.pdf
Please help me for no. 6(i) & 7(iii)

 

[xyz!]

For Q10, I will require the answers from (i) and (ii) (a).

Here are the solutions for Q7 (complex numbers Argand Diagram):



Hope this helps. Peace.

if in the same question..they asked fr the mod of z where arg(z) takes its greatest value..then how do v solve it sir?

 

[xyz!]

minato112 or whitecorp
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_3.pdf
Please help me for no. 6(i) & 7(iii)

Q.6)i) (consider cos(theta)=cosX)
L.H.S= 2cos^2(2X) -1 + 4[2cos^2 (X) -1]
=2[2cos^2(X) -1]^2 + 8cos^2(X) -5
on expanding and simplyfying furthr...u get R.H.S

Q.7)iii) sinX= 2/(x+2)
so 2/sinX=(x+2)
so 2cosecX=(x+2)
hence cosecX=(x+2)/2
which gives cosecX=(x/2)+1

Hope dis helps!

 

[xyz!]

can sum 1 pls solve d 2nd part of this question? with diagram! pls.....​

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[bamteck]

Q.6)i) (consider cos(theta)=cosX)
L.H.S= 2cos^2(2X) -1 + 4[2cos^2 (X) -1]
=2[2cos^2(X) -1]^2 + 8cos^2(X) -5
on expanding and simplyfying furthr...u get R.H.S

Q.7)iii) sinX= 2/(x+2)
so 2/sinX=(x+2)
so 2cosecX=(x+2)
hence cosecX=(x+2)/2
which gives cosecX=(x/2)+1

Hope dis helps!

Thanks mate
Can you help me with the no. 8 (ii) too ?

 

[xyz!]

i

Thanks mate
Can you help me with the no. 8 (ii) too ?

solved it for u..but writing idk how to write dwn integration sign n all...and i tried uploaing a pic as wel..bt ders sum problem..idk wt..
sry..!

 

[bamteck]

i
solved it for u..but writing idk how to write dwn integration sign n all...and i tried uploaing a pic as wel..bt ders sum problem..idk wt..
sry..!

:'(

 

[whitecorp]

:'(

Cheer up, here are the workings:



Hope it helps. Peace.

 

[whitecorp]

if in the same question..they asked fr the mod of z where arg(z) takes its greatest value..then how do v solve it sir?

In that case we shall consider two right-angled triangles to make the necessary calculations:



Hope this helps. Peace.

Edit: My bad, I read your question wrongly as asking to find arg(z) min. Will show you the workings for |z| when arg(z) is a maximum shortly.

 

[whitecorp]

Here are the workings for finding |z| when arg(z) is a maximum:



Hope this helps. Peace.

 

[shanky631]

Need help anyone
parthrocks
whitecorp

 

[shanky631]

 

[junyl93]

Anybody can help me with ques 3. I don't know how to do the showing part...