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Chemistry: Post your doubts here!
sorry ms says its D lemme edit the pic -
Chemistry: Post your doubts here!
aoa wr wb! use this eqn: P1V1 = P2V2 5 x 12 + 6 x 10 = (10 + 5) x p p =8 -
Chemistry: Post your doubts here!
Assalamoalaikum wr wb! Since when is gaseous bromine purple... :eek: This question is from N'10_12 Q 18 -
Chemistry: Post your doubts here!
aoa wr wb! 1 cuz benzene has none..other carbon has either some double bonds..or more than one hydrogen attached.. its the one attached to CH2 and a benzene ring -
maths exam!!!!
although i'm confident with the answers, yet cant assure u that i'd reply at the earliest... cuz i got another exam tomorrow.. -
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9709 Maths P1 Notes Here! :)
:ROFLMAO: u gave the exam today? right? well, honestly, I too prefer working it out...like the one in the video..! yet i've seen students finding that difficult, and rather learning the formula... it's your choice... ;) -
A Level Last Minute Revision Notes..
Aoa wr wb!! attached are the questions which i had doubt in.. might be you'd wanna go through them...contains the answers too ;) -
*~*~♦ тнᴇ αят ᴏƒ ɢяᴏᴏмɪɴɢ уᴏυя ѕᴏυʟѕ ♦~*~*
aoa wr wb awesome suggestion i'd say (y) -
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Maths P12!!! Not easy not hard
no discussion within 24 hours :( :D so cant tell now..otherwise mods will lock/ delete the thread :( -
A Level Last Minute Revision Notes..
Aoa wr wb! check out the 2nd post for chem p1 resources.. -
Chemistry: Post your doubts here!
Assalamoalaikum wr wb! need help, plz... ...:unsure: P.S. I'm reposting them :D -
maths exam!!!!
no discussion within 24 hours...so will telll u later.. :D -
Mathematics: Post your doubts here!
ok pm.. btw i dont think the rate thing was new... actually we did that in school...and i guess there were pastpaper questions on that.. -
Mathematics: Post your doubts here!
Assalamoalaikum wr wb! @alphabravocharlie N'11 P3 Q:8 ii -
Mathematics: Post your doubts here!
i remember there was a similar question to that in the pastpapers.. the binomial one... -
Mathematics: Post your doubts here!
aoa wr wb! really? :unsure: i gave the same paper...but apart from that Q:7 progression one, i don't think anything was different from pastpapers.. :D -
Chemistry: Post your doubts here!
Aoa wr wb! Q:15 Mr of CaCO3 = 100.1 Mr of CO2 = 44 CaCO3 àCaO + CO2 So 1 mol of CaCO3 will give 1 mol CO2 We have a total of 1200 million tonnes (=1200 x 10^6 x 10^3 g) of CaCO3 No of moles of CaCO3 = 1200 x 10^6 x 10^3 /100.1 This is equal to no of moles of CO2 = mass of CO2/44 Mass of CO2 =...