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  1. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    thanks for the explanations. :)
  2. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s07_ms_4.pdf Pls explain Q.1,b,part 1 , Q.3b, Q.4,c,part 2 and Q.7c.
  3. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    oh wait. I guess I did something wrong there. I should revise the chapter. Xtreme apologies for meddling with concepts :confused:
  4. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    I haven't read the whole post yet but let's look at this text now:" This is the whole problem. It's quiet the opposite! If the angular velocity actually changes and the force remains the same, then the radius would constantly decrease ( F = mw^2r ) which means that the motion will no longer be...
  5. Mustehssun Iqbal

    Help!!!

    There you go...copyrighted material :D http://www.xtremepapers.com/community/threads/a2-my-physics-revision-notes.12719/
  6. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    You didn't get my post right, I guess :confused: And no , when I wrote when the velocity is constant, there's no acceleration, I wasn't referring to rotational motion, but I was trying to refer to translatory motion, and later analyse both the motions in order to get to the right point. Read the...
  7. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    I didn't say that object moving in a circle with a constant angular velocity requires no force to keep it moving in that way.What I was trying to tell was An object can't move in a uniform circle with a constant angular velocity.
  8. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    And check my post again. It wasn't the direct answer to the question. The answer was given by Unique280. I just mentioned a correction in her answer, other than that, her answer was quite correct. :)
  9. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    "This has to mean that the at constant omega, there is a centripetal force ( Let's start from basic, F = ma. When the velocity is constant, there's no acceleration. When there's no acceleration, there's no resultant force on the object. Similarly, In circular motion, the effect of the...
  10. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    oh right :cry:
  11. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    Take a look at this unofficial derivation. Not a fair work, but for understanding :D Generally in simple harmonic motions, a = -( omega )^2 x a = -constant.x In this oscillation, x is also constant. Hence a = -constant.constant. Minus sign denotes the direction of acceleration so; a = constant...
  12. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    edit: defining equation of simple harmonic motion: a = - (omega ) ^2 x a = -( omega )^2 amplitude is max acceleration of the oscillations! Apologies!
  13. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    hehe :D The ball then moves down plane LA and rises up plane RA to its original height. The key word is right there, to it's original height. a= -(omega )^2 amplitude In this defining equation of simple harmonic motion, omega is constant throughout the motion of the ball, right?? But...
  14. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    by first part I mean the answer to the question :)
  15. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    Thanks to you- I didn't solve the first part :ROFLMAO:
  16. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    Omega does not depend on the radius, that's right. But there's still a centripetal on object right?? And we know, that F= ma, that when there's constant force, there's acceleration of the object. And when you recall the definition of centripetal acceleration, it's the rate of change of angular...
  17. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    So omega changes in its own rate, and F is directly proportional to the square of omega. Your answer is quite correct, increasing radius doesn't affect the value of omega. :) Pls correct me if I'm wrong. :)
  18. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    Omega changes, but not necessarily with radius. :)
  19. Mustehssun Iqbal

    A2 Physics | Post your doubts here

    good question and answer! Just want to note out that; Omega isn't constant. There's centripetal acceleration. The word acceleration denotes that there's rate of change of velocity- i.e. there's rate of change of direction of the object moving in circular motion. Pls do correct me if I'm wrong. :)
  20. Mustehssun Iqbal

    Practical Information (Physics and Chemistry)

    admin tala laga di jiye :D
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