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Mathematics: Post your doubts here!
Uhm, it'll be a bit hard to explain without drawing it .. I can try but if you want me to draw it , it'll take a little longer :c -
Mathematics: Post your doubts here!
Uhm, give me like 2 minutes. I'll brb. -
Mathematics: Post your doubts here!
I'll be here till like 11, which is 3 more hours I guess. I won't be here in the morning though. -
Mathematics: Post your doubts here!
Solved that earlier in the thread, it's like 4-5 pages back. -
Mathematics: Post your doubts here!
Just add up your values of the forces in the y-direction , and they've already given you the ones in the x-direction. Use Pythagoras to find resultant, and then use whatever to find the angle . Hope you got it x) -
Mathematics: Post your doubts here!
First equation is from A to B, second one is from B to C. From B to C your total distance is 120, and the total time taken will be 10 seconds. -
Mathematics: Post your doubts here!
You're welcome x) Thank you, my brain stopped e_e -
Mathematics: Post your doubts here!
First part is easy, since you know tension is a force use F= mass x acceleration For S1, only weight hanging is 3kg so: F= 3x10 = 30N For S2, both weights are hanging , so: F=5x10 = 50N Part 2 is a bit tricky, but easy to understand. When the masses fall , they'll have forces acting on... -
Mathematics: Post your doubts here!
Oh that's easy just make 2 simultaneous equations. Use s=ut+1/2at^2 So your first equation is: 55=5u+12.5a And second one is: 120=10u+50a Solve them simultaneously, you should get a=0.4 and u=10 m.s-1 -
Mathematics: Post your doubts here!
Ohlord, I can't think atm Can someone solve these 2 simultaneous equations for me. 5.5sinx = wgcosx And 5.5cosx + wgsinx = 7.3 -
Mathematics: Post your doubts here!
It's given you the maximum velocity, at max velocity acceleration is 0. So, since we have the equation for velocity , we need to change it to acceleration by differentiating it. This gives us , 12ot-3t^2 We take this as 0 and find the value of t 120t-3t^2 = 0 3t(40t-4) = 0 t= 40 Now that... -
Mathematics: Post your doubts here!
Ah all right, so it's asking for the speed of the particle at O, which is where it starts to move from. Obviously at this point the displacement will be 0, so we have to integrate the equation given for velocity and take it as 0. This is because of the rule, which I'm assuming you know... -
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Mathematics: Post your doubts here!
Ok , one second I'll show you. -
Mathematics: Post your doubts here!
Do you know how to use Pythagoras theorem? -
Mathematics: Post your doubts here!
They've given you one of the forces in the y-direction already, 75N . Since they mentioned positive y-direction that means upwards. Anything down will be taking as negative so you'll have to change the sign later. To find the other two forces use Pythagoras because you have the x-direction and... -
" I'm sorry " and " I apologize " mean the same thing, unless you're at a funeral.
" I'm sorry " and " I apologize " mean the same thing, unless you're at a funeral.- ZainH
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