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  1. ZainH

    Mathematics: Post your doubts here!

    I understood up until , a²+b² = 45 .. Now what are you substituting your values into?
  2. ZainH

    Mathematics: Post your doubts here!

    Cosπ/6= 16/hypotenuse Which gives the hypotenuse as 18 something. Which is wrong, it's not a right angle triangle :c
  3. ZainH

    Mathematics: Post your doubts here!

    For arithmetic progressions, a = 1st term, a+d = 2nd term, a+2d = 3rd term , and so on. d = the difference between consecutive terms. The first term here is 1 and the second term here is cos²x. SO, a=1 and a+d= cos²x We can find d from this, as we have two equations. Since a = 1 we can...
  4. ZainH

    Mathematics: Post your doubts here!

    You can't use sin since it's not a right angle triangle. For finding side AB, you know that angle BOA is 60, and two of your sides are 8. It has to be an equilateral triangle meaning AB is also 8. For finding BC you just use cos rule using triangle OBC. If you want I can solve it :c Also...
  5. ZainH

    Mathematics: Post your doubts here!

    Haha , relax. I'll go solve some papers and be back in ~20 minutes with questions.
  6. ZainH

    Mathematics: Post your doubts here!

    You guys make me feel dumb e_e .. Ill bring hard questions next time \:<
  7. ZainH

    Mathematics: Post your doubts here!

    Q. A geometric progression has the first term 4, and common ration (2x-3) , find the set of values of x for which the geometric progression has a sum to infinity. How o_O?
  8. ZainH

    Mathematics: Post your doubts here!

    Exactly lol, emphasis on TOMORROW.
  9. ZainH

    Mathematics: Post your doubts here!

    It's 41000, the calculations you wrote are correct. You probably did a mistake while calculating it.
  10. ZainH

    Mathematics: Post your doubts here!

    Lets hope our marks are just as high :rolleyes:
  11. ZainH

    Mathematics: Post your doubts here!

    I actually understood, not from what you explained.. but while reading I realized what we had to do xD Anyways thanks! You too doctorofelectronics
  12. ZainH

    Mathematics: Post your doubts here!

    I don't get it? ._________. Since g(x)= x-2 , and f=hg.. if h(x)= x²+3 , won't f=(x²+3)(x-2) ? And that gives something completely different D:
  13. ZainH

    Mathematics: Post your doubts here!

    If you could link me to the post, or tell me the page number that'd be great =D If you can't , then could you let me know how to solve it?
  14. ZainH

    Mathematics: Post your doubts here!

    How? Explain please =)
  15. ZainH

    Mathematics: Post your doubts here!

    If f(x)=x²-4x+7 for x>2 and g(x)= x-2 for x>2 The function h is such that f=hg and the domain of h is x>0 Q. Obtain an expression for h(x) .
  16. ZainH

    Thanks :c You too!

    Thanks :c You too!
    • ZainH
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  17. ZainH

    Mathematics: Post your doubts here!

    So I didn't need it in terms of x :p Now I get it, you switched the equation so the value for C wouldn't have a 'y' in it. Thanks for the , how many times has it been now? 3rd? Haha (y)
  18. ZainH

    Mathematics: Post your doubts here!

    That doesn't work :| K doesn't come as 8.5.
  19. ZainH

    Mathematics: Post your doubts here!

    All right, in that case I get : x²+8x+k²-52 = 0
  20. ZainH

    Mathematics: Post your doubts here!

    I tried that, I'm pretty sure I'm using b^2-4ac wrong. This is the equation I'm getting when they're equated: y^2+2k-4y-13 = 0 .. What's A , B and C... 4 terms. I forgot how to do these x_x
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