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Mathematics: Post your doubts here!
yes using the equation i posted above will give u a gradient of 1/2 so how come u say its wrong? -
Mathematics: Post your doubts here!
excuse me? why -1/3-1 and not 1/3-1 -
Mathematics: Post your doubts here!
dy/dx is 2(6x+2)^-2/3 is that what u got ? -
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Mathematics: Post your doubts here!
i think it would be better for him if he checked it from the book..isn't that better ? -
Mathematics: Post your doubts here!
open page 182 and check 13.4 the common perpendicular thingy because you need to know it so i can explain the third part..tell me if u had any doubts about that part ok ? -
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Mathematics: Post your doubts here!
do uk the common perpendicular method to find the normal of a plane from 2 other normals which is perpendicular to it ? -
Mathematics: Post your doubts here!
ok for question 7(ii) we got the equation of AB r = i +2j + 2k + t( 2i + 2j -2k) so any point lies on this line will have x= 1 +2t y = 2 + 2t z= 2-2t we can get the position vector of p from here. it says that OP (position vector) is perpendicular to the line AB which means that.. [(1+2t)i +... -
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Chemistry: Post your doubts here!
i am stuck in this question 2..i would appreciate it if someone can draw the graph and show it... -
Mathematics: Post your doubts here!
why do u need diagrams? and what is " @mkh@MKh@lid" :O:O -
Mathematics: Post your doubts here!
see.. dy/dx = tangent tangent = y/x which is same as tan theta = y/x so tan theta = dy/dx....find the gradient at point p and q by substituting the x values of p and q in the dy/dx u got (if u don't know how to differentiate tell me) tan theta = 1.5 at point p and tan theta = 0.75 at point... -
Mathematics: Post your doubts here!
tan theta = tangent is that what you r lookin for ? -
Chemistry: Post your doubts here!
because chlorine is a strong oxidizing agent so it will be strongly reduced by 2 electrons instead of one. As you go down the halogen group the element becomes less strongly as an oxidising agent and more strong as a reducing agent -
Mathematics: Post your doubts here!
we have r = 5/ 1-0.4t find t when the denomerator is equal to 0 so 1-0.4t = 0 t = 2.5 now any value higher than 2.5 will give u a negative value and we cant have radius in negative so the maximum value of t is just below 2.5 and the lowest one is t = 0 so 0 < t < 2.5 -
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Mathematics: Post your doubts here!
oops sorry i guess i was too late to answer ur question..u already got it -_-