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  1. U

    ECAT and MCAT Preparation: Post your doubts here!

    obviously.
  2. U

    thanku

    thanku
    • unique840
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  3. U

    ECAT and MCAT Preparation: Post your doubts here!

    rest ka baad main dekhungi. and 4 is not possible area = l*b perimeter = 2(l+b) lb=48 l=48/b 2(l+b) = 28 l+b = 14 replace l with 48/b quadratic equation banegi. solve it u will get 6 and 8 ab - bc means l - b 8-6 is 2
  4. U

    tm dua krna na...

    tm dua krna na...
    • unique840
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  5. U

    ok. i hope sbka test bohat acha ho and admission b mil jaye merit par. AMEEN

    ok. i hope sbka test bohat acha ho and admission b mil jaye merit par. AMEEN
    • unique840
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  6. U

    yar i hate essay. exam main iA hojayega. me sb kch ALLAH par chor rahi hun. i dun have much tym...

    yar i hate essay. exam main iA hojayega. me sb kch ALLAH par chor rahi hun. i dun have much tym to prepare.
    • unique840
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  7. U

    ECAT and MCAT Preparation: Post your doubts here!

    4 ka ans kia hai?
  8. U

    u which buk se studying?

    u which buk se studying?
    • unique840
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  9. U

    yar essay writing mene nae ki. and site par hain. years nae likhe. sample paper 1 is 2009 and so...

    yar essay writing mene nae ki. and site par hain. years nae likhe. sample paper 1 is 2009 and so on. karo to btana. mjhe kch help chahye ques main
    • unique840
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  10. U

    yar 2009 ka to easy hai. nw 2010 karing. thn 11 krna hai. frnd said k 11 mushkil hai. u ne try kiye?

    yar 2009 ka to easy hai. nw 2010 karing. thn 11 krna hai. frnd said k 11 mushkil hai. u ne try kiye?
    • unique840
    • Profile post comment
  11. U

    IBA admission test

    no
  12. U

    Mathematics: Post your doubts here!

    y = 1/cosθ y= cosθ inverse dy/dθ = -1(cosθ^-2)(-sinθ) dy/dθ = {sinθ/(cos^2)θ} dx/dθ = 0 + (sec^2)θ dx/dθ = (sec^2)θ dx/dθ = 1/(cos^2)θ dy/dx = {sinθ/(cos^2)θ} / {1/(cos^2)θ} dy/dx = sinθ
  13. U

    Mathematics: Post your doubts here!

    if its for A2 then the derivative of tan is sec^2
  14. U

    Mathematics: Post your doubts here!

    in part 2 u will diffrenciate the gradient of normal found in part 1. and equate it to zero to find the value of x
  15. U

    Mathematics: Post your doubts here!

    (u'v - v'u)/v^2 {(1-x)' (1+x) - (1+x)' (1-x)} / (1+x)^2 {(-1)(1+x) - (1)(1-x)} / (1+x)^2 {-1-x - 1+x} / (1+x)^2 -2/(1+x)^2 y = {(1-x)/(1+x)} ^0.5 y' = [0.5 {(1-x)/(1+x)}^-0.5] * {(1-x)/(1+x)}' we found the derivative of {(1-x)/(1+x)} above so substitute it here y' = [1/2 {(1+x)/(1-x)}^0.5] *...
  16. U

    Mathematics: Post your doubts here!

    is it AS or A2?
  17. U

    Mathematics: Post your doubts here!

    1/8 - (cos4x)/8 1/8 - [2(cos^2)2x - 1]/8 1/8 - [2(cos2x)^2 - 1]/8 1/8 - {[2(2(cos^2)x - 1)^2] - 1}/8 1/8 - {[2(4(cos^4)x - 4(cos^2)x +1] -1}/8 1/8 - {8(cos^4)x - 8(cos^2)x +2 -1}/8 1/8 - (cos^4)x + (cos^2)x -(1/8) -(cos^4)x + (cos^2)x cos^2x (-cos^2x +1) cos^2x(sin^2x)
  18. U

    Mathematics: Post your doubts here!

    ur welcum :)
  19. U

    lol :p

    lol :p
    • unique840
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  20. U

    Mathematics: Post your doubts here!

    it will be done by parts. u = lnx dv = 2x-2 du/dx = 1/x v = 2x^2/2 - 2x du = dx/x v = x^2 - 2x uv - integral of vdu lnx(x^2 - 2x) - integral[ (dx/x) (x^2 - 2x)] lnx(x^2 - 2x) - integral [ (x - 2)dx] lnx(x^2 - 2x) -...
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