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  1. U

    Physics: Post your doubts here!

    PV = nRT n is the number of moles. R is the molar gas constant number of moles(n) * avogadro constant(avg) = number of particles(N) n = N/avogadro constant k = R/avogadro constant R= avogadro constant * k PV = (N/avg) * (avg*k) * T avg cancels out therefore PV = NkT
  2. U

    Physics: Post your doubts here!

    if u apply the 10 N force on the lever, it will move upwards as it is pivoted at point P. therefore it is anticlockwise.
  3. U

    Physics: Post your doubts here!

    we have to find time for total error of 10%. it already has an error of 2%. means we have to find the time having an error of further 8%. the value given is Ao. 2% error is included in it. further error of 8% means Ao - 8% = 0.92Ao
  4. U

    Physics: Post your doubts here!

    25) intensity = A^2 I = A^2 2I = (A')^2 A' is the new amplitude replace I with A^2 2 (A^2) = (A')^2 taking square root on both sides A' = A * square root of 2 ans is B
  5. U

    Physics: Post your doubts here!

    33) resistance = (resistivity*length)/area volume is constant. volume = area*length length is doubled but volume is constant so area must be half. area = A/2 length = 2l resistance = (resistivity * 2l) / (A/2) = (4*resistivity*l) / A =4R
  6. U

    Physics: Post your doubts here!

    13) moments = force*perpendicular distance 5N and 10N force have anticlockwise moments. (5*2) + (10*2) = 30 N 20N force is clockwise. (20*3) = 60N resultant = 60 - 30 = 30N
  7. U

    Physics: Post your doubts here!

    the activity A0 is stated with 2% error. we hav to get the time for 10% ka error. means original se 8% error. if original is A0, then after 8% error, it will be 0.92A0. we will consider the expression: A = A0* e^(-lambda*time) lambda will be 0.693/half life lambda = 0.693/(5.27*365*24*3600) A =...
  8. U

    Physics: Post your doubts here!

    straight line passing through the origin. V=IR. resistance of resistor is constant so V is directly proportional to I
  9. U

    Physics: Post your doubts here!

    the question has the table of metals along with their work function energies. we hav 2 lights. one of wavelength 350 and one of 700. we will find the energies of both the lights and compare them with the work function energies. only potassium and light of 350 nm wavelength gives energy more than...
  10. U

    Mathematics: Post your doubts here!

    ans1) assume e^x = y y + y^2 = y^3 [y^3] - [y^2] - [y] = 0 y (y^2 - y - 1) = 0 y = 0 y = -0.62, 1.62 e^x = y e^x = 0 , 1.62, -0.62 ln(0) and ln(-0.62) is not possible x=ln1.62 x = 0.482
  11. U

    Mathematics: Post your doubts here!

    asn2) ln(x+2) - lnx = 2 ln [(x+2) / x] = 2 (x+2)/ x = e^2 x+2 = xe^2 x+2 = 7.39x 2 = 6.39x x=0.313
  12. U

    Mathematics: Post your doubts here!

    walaikum salam :) its better if we draw on a graph paper with compass and protractor cox it will give the exact diagram which we hav to use in the succeeding parts of the ques. if there is even a little variation in the diagram, it will give wrong answers.
  13. U

    Mathematics: Post your doubts here!

    post the ques in which u hav probs cox evry ques is of different type
  14. U

    Mathematics: Post your doubts here!

    the ans to part a should be multiplied with (1+kx). pick the terms of x^2 from the answer and equate it to zero. u will get the value of k
  15. U

    Physics: Post your doubts here!

    ur welcum :)
  16. U

    Physics: Post your doubts here!

    total power at constant speed = f(total) * v f1v1 - f2v2 = total power m1 g v - m2 g v = power gv(m1-m2) = total power
  17. U

    Physics: Post your doubts here!

    ur welcum :)
  18. U

    Physics: Post your doubts here!

    first find out the resistance of 1 resistor. (230^2) / 1000 = 52.9 ohms i) in parallel, the total resistance is 1/R = 1/52.9 + 1/52.9 = 26.45 ohms power lost = V^2 / R = (230^2) / 26.45 ohms = 2000 W = 2kW ii) in series, the total resistance is R1 + R2 = 52.9 + 52.9 = 105.8 ohms power =...
  19. U

    Physics: Post your doubts here!

    nov 08 q32 we will take all these in parallel. means there are 6 copper wires and 1 steel wire all in parallel with each other. resistance will be = 1/R = (1/10)*6 + (1/100) R = 1.6 ohms
  20. U

    Physics: Post your doubts here!

    q 37 of june 07: resistance = resistivity * length / area resistivity for both p and q is same as the material is same length is also same for both area = volume/height(or length) area will also be same cox volume and length of both p and q is same so resistance will be same
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