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  1. U

    Mathematics: Post your doubts here!

    ans9) integrate the derivative given. dy = (-k/x^3) dx dy = -k(x^-3) dx integrate the whole equation y = [-k(x^-2)] / -2 +c y = k/(2x^2) +c 18 = k/ (2) +c 3 = k/(2*4^2) +c solve both simultaneously and keep the values of k and c in the integrated equation
  2. U

    Mathematics: Post your doubts here!

    http://www.xtremepapers.com/community/threads/october-november-2011-question-papers-marking-schemes-examiner-reports.11543/page-11#post-176948
  3. U

    Mathematics: Post your doubts here!

    if ronnie has to win thn she must be the first to draw a yellow ball. julie draws the first ball which means julie hasto draw a green ball so that ronnie may draw a yellow one i.e P(gy). second possibility is that the first ball drawn by julie is green, the next by ronnie is also green and the...
  4. U

    Physics: Post your doubts here!

    ur welcum. :)
  5. U

    Physics: Post your doubts here!

    34)the initial reading is 4 V across the LDR. the resistance decreases when light increases. resistance and voltage are directly proportional. so the possible value of voltage will be less than 4 V that is 3V
  6. U

    Physics: Post your doubts here!

    33) at point s, voltage is v1. in the first branch the voltage is divided in 1:1 ratio. so v1 is 1 volts in second branch the voltage on 3 ohm resistor is 3/5 * 2 = 1.2 volts v1 - v2 = 1.2 - 1 = -0.2 volts
  7. U

    Physics: Post your doubts here!

    24) option D. its theory u have to learn the spectrum 28) D. cox the point negative charge has its field lines directed inwards
  8. U

    Physics: Post your doubts here!

    13) torque is force*perpendicular distance the perpendicular distance is not given. the distance given is hypotenuse so we will calculate the perpendicular distance by 0.6sin60 so torque will be 0.6sin60 * 8 = 4.2
  9. U

    Physics: Post your doubts here!

    8) u=o s=40 for the first 30 m: 2as = v^2 - u^2 2(10)(30) = v^2 - 0 v = 24.5 m/s this v will be initial speed for the last 10 m so for the last 10 m: s = ut + (1/2)at^2 10 = 24.5t + 5t^2 t = 0.38 or -5.3 so t is 0.38
  10. U

    Physics: Post your doubts here!

    welcum welcum :)
  11. U

    Physics: Post your doubts here!

    ur welcum :)
  12. U

    Physics: Post your doubts here!

    output power given is 4MW. efficiency is 80%. efficiency = output power/input power input power = output / efficiency input = 4MW/80% input = 5MW P=VI 5MW/25kV = I I= 200A
  13. U

    Physics: Post your doubts here!

    35) total resistance is 1/r = 1/1 + 1/2 + 1/5 r= 0.588 ohms total currrent is 5A v = IR v = 5*0.588 = 2.94 voltage is parallel does not divide so voltage in 2ohms resistor will be 2.94 volts v=ir 2.94 = i * 2 i = 1.5
  14. U

    Physics: Post your doubts here!

    14) rebounding height is half of initial means potential energy is half after rebounding. p.e = k.e therefore k.e is also half after the rebound final k.e = 1/2 of initial k.e 1/2*m*v^2 = 1/2 (1/2*m*u^2) v^2 = 1/2* u^2 taking square root on both sides v = u/sqr rt of 2 v/u = (u/sqr rt of 2) /...
  15. U

    Physics: Post your doubts here!

    speed is 8m/s which means 8m in 1 s so according to unitary method 50 m in x s 50 m cox one cycle is of 50 m x = 6.25s time period is 6.25 frequency is 1/6.25 = 0.16 hz for max speed: 2*pie*a*f for max speed we will take max amplitude. so it will be 2*pie*2*0.16 = 2.01 max kinetic energy...
  16. U

    Physics: Post your doubts here!

    ur welcum :)
  17. U

    Physics: Post your doubts here!

    ur welcum :)
  18. U

    Physics: Post your doubts here!

    we hav to xplain relation in which h is the constant of proportionality for example energy is directly proportional to frequency. when we equate energy and frequency we apply a constant h which is to remove the sign of proportionality therefore it is used as the constant of proportionality
  19. U

    Physics: Post your doubts here!

    p2 or p4?
  20. U

    Physics: Post your doubts here!

    ur welcum :)
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