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  1. U

    Physics: Post your doubts here!

    nov 2003 q5b)ii 1) at first the plane was normal to the magnetic field producing maximum flux. now it is parallel producing zero flux so change will be max - 0. that is the flux u calculated in parti i.e 9.18*10^-5 2) emf is change in flux/time 9.18*10^-5 / 0.2 4c) capacitor linearise the...
  2. U

    Physics: Post your doubts here!

    june 2003 q5c) r = mv/Bq v and B is given. charge of alpha is 2 times that of proton. and mass of alpha is 4 times that of proton. and for beta, the charge and mass is of electron. use the formula to find the radius
  3. U

    Physics: Post your doubts here!

    june 2003 q6ci) number of atoms = number of moles * 6.02*10^23 4.67*10^15 = (mass/mr) * 6.02*10^23 4.67*10^15 = (mass/90) * 6.02*10^23 mass = mass will be in grams so change it in kg
  4. U

    Physics: Post your doubts here!

    nov 2002) when 1/2 f0 is impressed then the time period will be 2T. so every impulse is after 2 oscillations. means alternate oscillations are energized. so there is continuous increase of amplitude at every impulse.
  5. U

    Physics: Post your doubts here!

    june 2002 q4b) at max displacement the p.e is maximum. and at mean position it is zero. so the graph will be at max at max displacement. but it will be all above xaxis because energy can not be negative. c) t = 2pie * sqr root of mass / sqr root of 'k' when mass decreases time period also...
  6. U

    Physics: Post your doubts here!

    b) the current will enter at A and leave at C. it will either follow A-B-C or A-D-C. take both passages in parallel. it will be: 1/R = 1/8 + 1/8 R = 4 ohms
  7. U

    Physics: Post your doubts here!

    A) between A and B: means current is entering at A and leaving at B. when this happens, the circuit is as shown. means the passage of current is either directly from A to B or from A-D-C-B. we will take both the passages in parallel. so the calculation for parallel resistance would be: 1/R =...
  8. U

    A2:My Physics Revision notes

    sure. prayers to sab k liye hoti hain :)
  9. U

    A2:My Physics Revision notes

    thanku so much :)
  10. U

    Physics: Post your doubts here!

    lol :p
  11. U

    Physics: Post your doubts here!

    first find out the resistance of 1 resistor. (230^2) / 1000 = 52.9 ohms i) in parallel, the total resistance is 1/R = 1/52.9 + 1/52.9 = 26.45 ohms power lost = V^2 / R = (230^2) / 26.45 ohms = 2000 W = 2kW ii) in series, the total resistance is R1 + R2 = 52.9 + 52.9 = 105.8 ohms power =...
  12. U

    Physics: Post your doubts here!

    1/2 m c^2 = 3/2 kT c^2 = 3k/m T 3k/m is a constant. c^2 is directly proportional to T 500^2 = constant * 300 (initial temp n rms speed) constant = 2500/3 now the twice of initial speed would be 1000 so: 1000^2 = 2500/3 * T T = 1200
  13. U

    Mathematics: Post your doubts here!

    ur welcum :)
  14. U

    Mathematics: Post your doubts here!

    ur welcum :)
  15. U

    Mathematics: Post your doubts here!

    p31 or 32 or 33?
  16. U

    Mathematics: Post your doubts here!

    ur welcum :)
  17. U

    Mathematics: Post your doubts here!

    part2) y = 6sin(2x) + 3 at y = 0 0 = 6sin(2x) +3 6sin(2x) = -3 sin(2x) = -1/2 2x = sin inverse of (1/2) keeping the calc in radian mode the value of sin is pie/6 it is -1/2 so sin -ve is in 3rd and 4th quadrant so 2x = 7pie/6 or 11pie/6 x = 7pie/12 or 11pie/12 smallest value of x will be 7pie/12
  18. U

    Mathematics: Post your doubts here!

    part1) a represents amplitude i.e 6 b represents number of cycles i.e 2 c represents the value of y from where the graph is starting i.e 3
  19. U

    Mathematics: Post your doubts here!

    which part?
  20. U

    Mathematics: Post your doubts here!

    i m replacing theta with x 1/(2cosx +i - i2sinx +2 -i) +i -i cancels out 1/(2cosx -i2sinx +2) multiply and divide the whole fraction with the conjugate [1/(2cosx + 2 - i2sinx)] * [(2cosx + 2 + i2sinx) / (2cosx + 2 + i2sinx)] in the denominator: ( (2cosx + 2 + (2cosx + 2 + i2sinx) ) - i2sinx) *...
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