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can someone pls help me with ques 27? thank you
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s11_qp_11.pdf
hmm.. let's see.. it is given : 500 lines in 1 mm, therefore, 1 line = 0.001/500 = 2 * 10^-6
the general equation to find the maximum no. of order, i.e the maximum no. of images = d/lamba = (2 * 10^-6)/(600*10^-9) = 3.33 so, the maximum no. or order is 3, but, you have to consider the other 3 images at position Z, hmm.. firstly, zero order is at position Y, so, that's one image, then there are three orders, i.e, three images at position X as well as at position Z, therefore, altogether there are 7 images, 3 images at position X, 1 image at position Y, and 3 images at position Z.. I hope you understand my explanations.. heheh..
umm...i'm sorry but i still don't get it. how do you know there is only one at Y and 3 at X and Z. 8) u=o
13) torque is force*perpendicular distance
24) option D. its theory u have to learn the spectrum
33) at point s, voltage is v1. in the first branch the voltage is divided in 1:1 ratio. so v1 is 1 volts
34)the initial reading is 4 V across the LDR. the resistance decreases when light increases. resistance and voltage are directly proportional. so the possible value of voltage will be less than 4 V that is 3V
ur welcum.Thanks, unique840. It's really simple once you break it down. Thank you once again.
36:I = V/ R , 3 / 6 = .5A. now use this to find the voltage consumed by the internal resistance which is .5 X 2 = 1 V , Terminal voltage will be 3-1= 2 volt, useful output power => p=VI 2 into .5 = 1 W
AoA!
Assalamoalaikum wr wb!
hmm.. I'm gonna make it simple.. I have calculated that the no. of maximum order is 3, we know that at position Y, it is zero order, which means, only one image can be seen at position Y, next, at position X, there are 1st order which is right above position Y, 2nd, and 3rd order, therefore, there are three images at position X, same goes to position Z, 1st order, which is right below position Y, then 2nd and 3rd order, thus, there are seven images altogether..
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