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Physics: Post your doubts here!

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hey can anyone please explain how to calculate change in momentum for these values: Mass=0.045 kg, Initial velocity=4.2 m/s Final velocity=-3.6 .The negative sign is creating a confusion. the formula is given : mass*(initial+final) in the mark scheme.it's Nov/2002 P2 Qs3.thank you.



momentum means the sum of mass intio velocity p = mv
change in momentum means the difference in mv before and after colision or after the particular action.

so finding the change in momentum frst consider the starting momentum/initial momentum

which is mv = (0.045)(4.2) = 0.189kgms-1.....taking velocity here positive considering the direction.
now when particle collides or rebounds back the direction will be changed, as velocity is vector quantity.
therefore it is represented wid a negative sign.

take out the momentum after collision mv = (0.045)(-3.6) = -o.162kgms-1
now U are having two momentums jxt take out the differnce

(mv) - (mv).... (0.189) - (-0.162)
delta p = change in momentum = o.351 ANS
 
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as the previous questions are answered by Usman a.k.a Mani (thanks to him) so u r left with 22 which is Mr Young Modulus = Stress over Straaain! , u need to know the strain on your shoulders, lets get over with the stress first. which will be Force divided by Pi d^2 / 4. i.e 20N / (pi 5* 10^-4)^2 / 4 which will give u 10.2 into 10^-7 Pa. now strain is equal to Stress over Y.M divide it nd u will get 5.1 into 10^ -4% which is A. But the freaking marking scheme says its B. :|
 
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one more question paper, please.
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w08_qp_1.pdf
questions 27, 34, 36.
Thank you very much :)
ok so 27th: speed of g x u v i m r rays: 3 into 10^8 !!! so we need to know lambda i.e wavelength produced which will be twice the distance between the adjacent maximas ( i dnt knw why i have to make it twice but it works or maybe twice the distance between maximas gives u wavelength) anyway so 3 into 10^8 divided by .030 meters is = 1 into 10^10Hz i.e C!

34: its simple contrary to the first impression to this mcq: lets calculate the total current which the battery can supply for 2 second intervals: I = Q/t so 100,000 C / 2 s = 50,000 A! Now simply divide it with 200 A to get the number of times it can give this much current, provided the battery isn't gonna get recharged.

36: ok so we want to know the internal resistance of the battery in order to calculate the current in the circuit. well we are given with the voltage of the battery 9 volts and the terminal voltage 7.5 volts! so the volts used by the internal resistance is 1.5 volts!!!

lets make two equations as we know the current is same: so I = 1.5 / R1 ( eq 1)
(R1 being the internal resistance)

I = 9 / 15 + R1 (eq 2) now solve these two equations simaltaneously u will get R1 to be 3 Ohms!!! hurray!!!

so now just simply calculate the current. I = V / R => 9 / 18 = .50 Amperes which is B!
 
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momentum means the sum of mass intio velocity p = mv
change in momentum means the difference in mv before and after colision or after the particular action.

so finding the change in momentum frst consider the starting momentum/initial momentum

which is mv = (0.045)(4.2) = 0.189kgms-1.....taking velocity here positive considering the direction.
now when particle collides or rebounds back the direction will be changed, as velocity is vector quantity.
therefore it is represented wid a negative sign.

take out the momentum after collision mv = (0.045)(-3.6) = -o.162kgms-1
now U are having two momentums jxt take out the differnce

(mv) - (mv).... (0.189) - (-0.162)
delta p = change in momentum = o.351 ANS
yes i understand that but don't we take final momentum-initial momentum?
 
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how the image is formed in MRI.....I HAVE READ IT MULTIPLE TIMES BT I NEVER SOME TO UNDERSTAND HOW THESE protons cud every make an image.....i cnt get the basic idea.....
 
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yes i understand that but don't we take final momentum-initial momentum?

hmm.. actually, you can use : final momentum - initial momentum, but the answer will be negative, so you just ignore the minus sign.. that's what my teacher told me.. heheh..
 
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yes i understand that but don't we take final momentum-initial momentum?

or, you just remember this, if the object is hitting a vertical wall, and then it rebounds, the velocity is changing its direction, therefore, change in momentum will be initial + final momentum, but, if the object just goes straight without hitting anything, and it changes its speed (not with negative sign), you must use final momentum - initial momentum.. heheh.. :)
 
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yes i understand that but don't we take final momentum-initial momentum?

oh! one more thing, if you use final - initial momentum, the answer will be a negative value, it is true because the the mass is moving in the opposite direction (negative velocity), so as the momentum, as momentum is a vector quantity, therefore it has direction.. so, you just ignore the minus sign.. heheh..
 
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yes i understand that but don't we take final momentum-initial momentum?

AoA

hmm.. actually, you can use : final momentum - initial momentum, but the answer will be negative, so you just ignore the minus sign.. that's what my teacher told me.. heheh..


as was quoted wisely by anonymus! U can ignore sign! as it jxt shows the direction. We are asked fr change in momentum. MArks will be given for that.:)
 
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10) f=ma
60=30a a= deceleration
a= -2ms-2 (negative sign indicates that itx decelaration)


now apply formula fr acc. >>> a=(Vf- Vi)/t

-2 = (Vf - 3)/0.50

Vf = 2ms-1 ans.

15) according to conservation of momentum same will be the momentum at both sides
so at left side is MV= 2 * 2 =4

so will the momentum at right side MV= 1 * 4 = 4
now we know the velocities of both the objects moving!
take out the kinetic energy of both trolleys movingthese velocities
by the formula 1/2mv^2
the K.E of left will be 8j
of right will be 4j
the total stored in the spring will be 8+4 = 12j
Thank you very much. :) Allah bless you.
 
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34) q is the charge! it can be found out by Q= IT where I is the current in AMperes and t is the time in sec.

now a car needs 200A till 2 seconds to start means it needs Q=IT 200*2 400C of charge.


now consider car being fully charged means it have 100KC
of charge!
cnvrt kilo coulomb into coulomb
means 100810^3 = 100000C

now divide it by the charge needed per start for the car!


100000/400 = 250 times is the ans!
Thank you. :)
 
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AoA




as was quoted wisely by anonymus! U can ignore sign! as it jxt shows the direction. We are asked fr change in momentum. MArks will be given for that.:)
ok so if we solve it like that and get negative sign answer but ignore it ,our marks won't get deducted.and thank you to both of you.
 
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What about Q13 of the same paper?
to calculate the tension: use the torque given for wheel q => T = F into s so 3 = F into radius of Q wheel .05. tension in the BELT is 60 N,
same force will be transmitted to the next pulley : so 60 into the radius of p pulley will give u the torque (radius is the perpendicular distance from the line of action of the force). divide this radius by 1000 to get in meters. it comes 4.5 Nm. option D.
 
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