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The Line of Best Fit ...?
Hei guys, I have a little doubt with A-level Chemistry Paper 5. Usually there is a part which asks for a graph plotted according to given data and the line of best fit is required. I'm not sure if the line of best fit can sometimes be a curve to show certain relationships... What do you think? -
Further Mathematics: Post your doubts here!
Sorry I don't have the answer here... Can you show me how you worked out the result? -
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Hi, i'm saira!
Nice to meet you Saira. Definitely Xtremepapers is the best place for past papers and discussion. :D- DragonCub
- Post #5
- Forum: Welcome Lounge
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Physics: Post your doubts here!
The original form of the equation for ideal gas is p V = n R T where n = the mole number of gas R = ideal gas constant T = temperature in absolute scale In derivation, N = the number of gas molecules = n × NA (Avogadro's constant) k = Boltzmann's constant = R ÷ NA So you can see p V = N k T... -
Further Mathematics: Post your doubts here!
Hei guys, I got stuck on a question about parametric equations. Here is the problem: I really could not get through the integration part. Can anyone lend me a hand? Thanks in advance. -
Further Mathematics: Post your doubts here!
Ha, I got it. Thanks abcde -
Further Mathematics: Post your doubts here!
Dude I'm not very familiar with the "Z form" you've mentioned. Can you tell me something about it? :P -
Physics Question help?
It will be quite easy if you apply the formula [power = force × speed]. In the question the power is given as 35kW, or 35000W; the speed 144 km/h, or 40 m/s. The car is travelling in maximum speed, this means the speed is constant. Force acting against the car should be equal to that driving the... -
I'm Back :P
Hi guys I'm sorry it's been a long time since I visited XPF last time (I registered a year ago) and I am surprised that XPF has experienced such an undate. I hope that I can get involved into discussions again. (Of course you can treat me as a newcomer :P) And by the way, I'm learning Further...- DragonCub
- Thread
- Replies: 16
- Forum: Welcome Lounge
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"A failure to prepare is a preparation to fail." I believe this.
"A failure to prepare is a preparation to fail." I believe this.- DragonCub
- Profile post
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Mechanics P4 question!
7 (i) Plug in t = 10s into v = 800 / (t^2) - 2, you get v = 800 / (10^2) - 2 = 6 m/s That is velocity, then a = 6 / 10 = 0.6 m/(s^2) 7 (ii) Differentiate the velocity-time function. You get dv/dt = -1600 / (t^3). This is acceleration's value during 10s and 20s. -1600 / (t^3) = -0.6 t = 13.9s 7... -
Mechanics P4 question!
6. (ii) (a) Yes they have gravity acting on themselves but that's not the only force. Tension in the string is also involved. From (i), the acceleration should be calculated out to be 1 ms^(-2). Use s = ut + 0.5 at^2 to solve (ii) (a). t = 2, a = 1, u = 0. So s = 0.5 * 1 * 2^2 = 2m. P is... -
p1 help needed
f(x) = k ------> 4 - 3sin(x) = k has so solution, the answer is simply the values those are out of the range of the function. f(x) has range 1 <= f(x) <= 7, so k's value should be k < 1 or k > 7. -
maths P1 nov 2008 why -ve ????
You can see that in the equation, the variable x affects the value of -b cos(x) only. For cos(sth), the value should be >=0 and <= 1. So in the equation, 0 <= b cos(x) <= b. Hence 0 >= -b cos(x) >= -b. Maximum 10, so a + 0 = 10, a = 10 Minimum -2, then a + (-b) = 2, b = 12 -
P1 June 2009 Q4-ii
Simply solve it as an algebraic equation: 6 sin(2x) + 3 = 0 sin(2x) = -1/2 2x = 2pi /3 x = pi/3 -
chem: shocking
The answer should be B, I think too. For A, Bromine gas itself is non-polar, so it definitely CAN dissolve in non-polar solvents. A is wrong. For B, according to the ideal gas law, 1 mole of any gas at RTP occupies the same volume (24 dm^3). On the other hand, The average molar mass of air is... -
chemistry p22 help!!
To (i), the delta H is -ve, meaning that the forward reaction is exothermic, i.e. from SO2 + O2 to SO3, heat is given out, raising the temperature of the surroundings. So to favour the forward reaction (i.e. move the equilibrium more towards the products), according to Le Chartlier's Principle... -
Help please......
The answer to Q 29 IS D. First, think about what condition makes a circular motion? The force is required to be ALWAYS PERPENDICULAR TO the direction of motion!!!! But is it like this way in the question?? The force on the electron acts towards the upper plate all the time, it goes no longer...