• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. Anum96

    Marraige Age?

    LOL. Stop transferring knowledge this way. None of us is dead sure about Hazrat Aisha(R.A)'s marriage time. Stop with the arguments. We all should open Quran and search for it. That will surely be more authentic than any other source or book.
  2. Anum96

    *walks straight* O_o

    *walks straight* O_o
    • Anum96
    • Profile post comment
  3. Anum96

    A letter from saitan (shaitaan) ..

    Ouch.
  4. Anum96

    Get cape. Wear it. Fly..

    Get cape. Wear it. Fly..
    • Anum96
    • Profile post
  5. Anum96

    Marraige Age?

    I think 25 or 26. #SayNoToEarlyMarriage. :p They should get married when they know they can do something for themselves in their life.
  6. Anum96

    Mathematics: Post your doubts here!

    Put any value of x you'll get a positive result. Why? Because the squared term of both the expressions is positive. You can even use your sketching skills to show.
  7. Anum96

    Mathematics: Post your doubts here!

    Hahaha. Oops. Its okay. Youll get 5x/12 as the middle term with that. (y) You're welcomee! ;)
  8. Anum96

    sat 1

    HAHAHAHA. ohhhhh :p
  9. Anum96

    ...... :p

    ...... :p
    • Anum96
    • Profile post comment
  10. Anum96

    And may Allah accept that prayer! :) Amen. Thank you so much! :D

    And may Allah accept that prayer! :) Amen. Thank you so much! :D
    • Anum96
    • Profile post comment
  11. Anum96

    Mathematics: Post your doubts here!

    Okay so here it is: Bring the denominators up. 3(3 + 2x)^(-1) + (-x – 2)[(x^2 + 4)^(-1)] Expand. 3(3 + 2x)^(-1) + [-x (x^2 + 4)^(-1)] – [2((x^2 + 4)^(-1)] You need to separately expand : (3 + 2x)^(-1) & (x^2 + 4)^(-1) So, (3 + 2x)^(-1) = 3^(-1)[1 +2x/3]^(-1) = 1/3 (1 + 2x/3)^(-1) 1/3...
  12. Anum96

    Mathematics: Post your doubts here!

    tell me ur ans to i :p
  13. Anum96

    sat 1

    you arent giving the redesigned one. are you? :p
  14. Anum96

    Indecisiveness.....

    Indecisiveness.....
    • Anum96
    • Profile post
  15. Anum96

    sat 1

    http://www.ielts-karachi.com/sat-test-preparation-in-karachi-sat-classes-in-karachi-sat-institute-in-karachi-sat-course-in-karachi-sat-exam-in-karachi-sat-test-in-karachi-sat-teacher-in-karachi-lahore-islamabad-faisalabad-h/
  16. Anum96

    sat 1

    Which city?
  17. Anum96

    No more than a passing fancy..

    No more than a passing fancy..
    • Anum96
    • Profile post
  18. Anum96

    Hahaha. Oh I Love it! .... But... Only as long as I know it. :p Thank you btw. B-)

    Hahaha. Oh I Love it! .... But... Only as long as I know it. :p Thank you btw. B-)
    • Anum96
    • Profile post comment
  19. Anum96

    Mathematics: Post your doubts here!

    ii) Maximum point. Put dy/dx = 0 dy/dx ; y = e^(2sinx) * cosx u = e^(2sinx) u’ = 2cosx*e^(2sinx) v = cosx v’ = -sinx dy/dx = uv’ + vu’ 0 = [e^(2sinx)* -sinx ] + [cosx*2cosx*e^(2sinx)] 0 = e^2sinx [-sinx + 2cos^2(x)] 0 = -sinx + 2cos^2(x) Sinx = 2(1 – sin^2(x)) sinx= 2 – 2sin^2(x)...
  20. Anum96

    Mathematics: Post your doubts here!

    Dy/dx = 6ye^3x/(2+e^3x) Dy/y = 6e^3x/(2+e^3x)dx ʃ dy/y = ʃ 6e^3x/(2+e^3x)dx lny = 6 ʃ e^3x/(2+e^3x)dx lny = 6 (1/3)ln(2+e^3x) + C Now you have y = 36 and x = 0. Use them to find C. ln36 = 2ln(2+e^3(0)) + C ln36 = 2 ln(2 +1) + C ln36 = 2ln3 + C ln 36 = ln3^2 + C ln 36 =ln9 + C ln36 –...
Top