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Math p12 tomorrow (Best of luck and comment after exam!!!)
just kidding lol xD What did you get for the rate of change of y and the last part of Q7? -
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CIE exam tension is killing me :/
tension is for pussies <- wise words- imanmalik
- Post #67
- Forum: Welcome Lounge
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Inverse Functions question.
thank you so much...i was like...HOW THE HELL CAN I GET SUCH AN EASY QUESTION WRONG xD -
Mathematics: Post your doubts here!
But the thing is i got that answer. And according to the markscheme it should be f-1g(x) = 1/((2(x^2 -3)) -
Inverse Functions question.
F(x) = 2x+1 f(g)= x^2 - 2 find an expression for f-1 g(x) so the inverse of f is y=2x+1 -> (y-1)/2 =x -> y= (x-1)/2 then you punch in the value of g ((x^2 - 2)-1)/2=y (x^2 - 3)/2 = f-1g(x) but the mark scheme says F-1(x)= 1/(2(x-1) and f-1g(x) = 1/(2(x^2 - 3)) How? -
CIE exam tension is killing me :/
integration is just like differentiation but in reverse- imanmalik
- Post #55
- Forum: Welcome Lounge
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Mathematics: Post your doubts here!
two questions. Question 3. I'm getting the values for b and a the wrong way around. Why? (s11 paper13) Question 11 (iv) Isnt the inverse of f y= (x-1)/2 ? The mark scheme says something completely different. (s11 paper11) -
The official count to 10,000 topic
even dyslexia can't change this one lol 55 -
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