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  1. S

    HOWS UR STATISTICS PAPER 62??????

    u both r wrong! For independent events, that is events which have no influence on one another, the rule simplifies to: That is, the probability of the joint events A and B is equal to the product of the individual probabilities for the two events.
  2. S

    S1 paper6 how was it????

    n both permutation n combination cud be slectd depending how u tackle the question...fr example fr the last q 3rd last part, by using permutation it cud be 9P3 n by using combination it wud be 9C3x3!...both r correct...cuz once u hav chosen the 3 cardz frm 9, u also hav to arrange them in a line...
  3. S

    S1 paper6 how was it????

    dude it wasnt 14...jus lemme giv u an example...wat if neither green nor pink was selected...even then the pink n green wudnt be together cuz they r not selected at all...so like wise pink alone cud be selected n not green..n green alnone can be selectd n not pink...n both can be selectd...so da...
  4. S

    HOWS UR STATISTICS PAPER 62??????

    we can use permutation n combination both fr last q...if using permutation, it wud be 9P3..n if usin combination then 9C3x3!
  5. S

    HOWS UR STATISTICS PAPER 62??????

    lol nightmare! is dis ur own theory about independent eventz? LMAO!!!!! two eventz can only n only be independent if P(QandR)=P(Q)xP(R)...this wasnt da case here cuz P(QandR) was zero..so they were not independent!!!
  6. S

    HOWS UR STATISTICS PAPER 62??????

    fikar na kar boi, gt bht gire gi!! ;)
  7. S

    S1 paper6 how was it????

    phattay gi!!!
  8. S

    S1 paper6 how was it????

    it was of 2 marks, maybe u'll get 1
  9. S

    S1 paper6 how was it????

    yes they were mutually exclusive bcuz P(QandR)=0...but they were not independent
  10. S

    HOWS UR STATISTICS PAPER 62??????

    i got 476
  11. S

    HOWS UR STATISTICS PAPER 62??????

    cnetral tendency means mean, mode and median
  12. S

    S1 paper6 how was it????

    u had to find da probability distributiion dat was P(x=0)=1/7, P(x=1)=4/7 and P(X=2)=2/7...then u had to find the mean by finding the sum of the product of X and its probability. ie mean= 0x1/7 + 1x4/7 + 2x2/7 = 8/7
  13. S

    HOW WAS PHY P33?????

    btw i took 0.1..so %age wud be = 0.1/time x100
  14. S

    HOW WAS PHY P33?????

    uncertainy wud be 0.1-0.01...it dependz wich stopwatch r u using..if digital then 0.01 n if analogue then 0.1...so no need to worry!!
  15. S

    LAtest news from LHR..Not yet confirmed..

    ya...just rumors! it was ditto same paper..luvd it! :P
  16. S

    Lums

    who da hell says k lums require 3 As....i got admission n i just need 2 B's n 1C..datz it!
  17. S

    Lums

    got a letter 2 fm sse...submited da fees! :D
  18. S

    Physics p33 errors

    hav a luk at Nov 03 paper 05 Q 1...the same q about diode!!!
  19. S

    Physics p33 errors

    hmm. so u givin p33? hwz ur prep?
  20. S

    Physics p33 errors

    hey guyz...i've heard that the 2 qs that r cumin wud be of oil viscosity n a diode exp. i wantd to ask one thing..yar in practicalz there is one qs abt graph n the other in which u hav to tell abt 4 errors n how to improve those errors...do u hav any idea wat the errors n their improvemnts can...
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