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  1. The Sarcastic Retard

    Chemistry: Post your doubts here!

    There are two lone pairs. H-O-H isnt 180 coz of lone pair, CO2 is pure sp hybridization without lone pair, hence its linear.
  2. The Sarcastic Retard

    Chemistry: Post your doubts here!

    10) A) HSO3 is a proton acceptor. Proton acceptor is a base. B) SO2 is a reductant. C) 2H+ donated proton to SO3(-2). Hence its base. D) SO3(-2) is an oxidant.
  3. The Sarcastic Retard

    Chemistry: Post your doubts here!

    x = 104.5 y = 109.5 z = 107.5 y -> z -> x
  4. The Sarcastic Retard

    ty :*

    ty :*
  5. The Sarcastic Retard

    :3

    :3
  6. The Sarcastic Retard

    breeze kissing my face, not me. -_-

    breeze kissing my face, not me. -_-
  7. The Sarcastic Retard

    Focuses on the water ground mixture. Feeling the breeze kissing my face. #HopeGWstops#

    Focuses on the water ground mixture. Feeling the breeze kissing my face. #HopeGWstops#
  8. The Sarcastic Retard

    Beauty of nature. ♥

    Beauty of nature. ♥
  9. The Sarcastic Retard

    Chemistry: Post your doubts here!

    concentration too yea?
  10. The Sarcastic Retard

    Expected 2015 November papers. DO VOTE.

    asadalam as we discussed. :P According to me it should be Medium. :cool:
  11. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Thanks. :)
  12. The Sarcastic Retard

    Chemistry: Post your doubts here!

    How can we know if the fwd rate is increase or not by the shifting of eq to fwd direction? Check out C - My confusion.
  13. The Sarcastic Retard

    Chemistry: Post your doubts here!

    How is this possible? :/
  14. The Sarcastic Retard

    Chemistry: Post your doubts here!

    It should be in diagonals. In B overall DPM is +---->
  15. The Sarcastic Retard

    Chemistry: Post your doubts here!

    This question is pretty easy. 2EN (Cl) are in diagonals which cancels each other out, in no other option there u see EN elements in diagonal hence D
  16. The Sarcastic Retard

    Chemistry: Post your doubts here!

    C3H7OH + 4.5O2 --> 3CO2 + 4H2O 0.1 mol of acid was burned. 0.45 mol of oxygen used. Volume of oxygen = 0.45 x 24 = 10.8 dm^3 Volume of CO2 = 7.2 dm^3 (ratio) Initial volume of oxygen = 12 dm^3 12 - 10.8 = 1.2dm^3 left Dont forget to add 7.2dm^3 of co2. 1.2+7.2 = 8.4dm^3
  17. The Sarcastic Retard

    hehe xD

    hehe xD
  18. The Sarcastic Retard

    Physics Paper-21 !!

    p = mv = scaler * vector = vector.
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