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Toughest Math P3 doubts! Here.
i tried it and i was getting the same result. check for any sign errors and stuff. Also are u writing mechanics 1 this friday -
Toughest Math P3 doubts! Here.
uhmm .............because ............. i forgot that XD . But it should give the same result since u derive the formula above by the method i stated -
Toughest Math P3 doubts! Here.
for that you just convert the tan2x and tanx to sin and cos; and then use the integral of :- f '(x) / f(x) = ln |f(x) | +c -
Toughest Math P3 doubts! Here.
https://drive.google.com/open?id=0ByjLCrFu0tDHM3RrbVA0MmhOV1E -
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Toughest Math P3 doubts! Here.
i did it like this . Also do u remember what roots u had for the complex number question -
Toughest Math P3 doubts! Here.
the Yh i got all of them im pretty sure. Only one im not sure about is the roots to complex equation cause i couldnt cross check it Do you remember the trig question ? -
Toughest Math P3 doubts! Here.
thanks man Paper 32 was pretty easy -
Toughest Math P3 doubts! Here.
BTW just a general question. For sketching an argand diagram will we do it on the answer sheet or on graph paper? -
Toughest Math P3 doubts! Here.
yh you can use that or take our sec^2 x common so we get something like :- sec^2 x(sec^2 x - 1) and equate it to (tan^2 x + 1) * (tan^2 x) -
Toughest Math P3 doubts! Here.
would like to point out that you got tan^4 x - tan^2 x when you should be working to get tan^4 x +tan^2 x -
Toughest Math P3 doubts! Here.
thanks alot. is anyone here also writing further maths? -
Toughest Math P3 doubts! Here.
how to find beta in this? (its s14_qp31)