Toughest Math P3 doubts! Here.

[Thought blocker]

part II
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how much did u get in this paper?
Well thanks a lot, i will upload all this by tomorrow

 

[rgrock98]

i'm sorry i was working, just got free now. So here it is:
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wasn't hard...just a little different or rather 'interesting' xD

would like to point out that you got tan^4 x - tan^2 x when you should be working to get tan^4 x +tan^2 x

 

[Thought blocker]

would like to point out that you got tan^4 x - tan^2 x when you should be working to get tan^4 x +tan^2 x

its coz she used sec^4(x) = 1 + tan^4(x)
thats the mistake, I didnt saw that, coz i thought she got answer so would be correct xD
sec^4(x) = (1 = tan^2(x))^2 techgeek
now u will get it.

 

[rgrock98]

its coz she used sec^4(x) = 1 + tan^4(x)
thats the mistake, I didnt saw that, coz i thought she got answer so would be correct xD
sec^4(x) = (1 = tan^2(x))^2 techgeek
now u will get it.

yh you can use that or take our sec^2 x common so we get something like :- sec^2 x(sec^2 x - 1) and equate it to (tan^2 x + 1) * (tan^2 x)

 

[Thought blocker]

yh you can use that or take our sec^2 x common so we get something like :- sec^2 x(sec^2 x - 1) and equate it to (tan^2 x + 1) * (tan^2 x)

Yeah bro, it depends, what or which method strikes to us

 

[rgrock98]

BTW just a general question. For sketching an argand diagram will we do it on the answer sheet or on graph paper?

 

[Thought blocker]

BTW just a general question. For sketching an argand diagram will we do it on the answer sheet or on graph paper?

No graph paper, just on answer sheet.

 

[Thought blocker]

Good luck guys :

This was the complexiest question i ever saw

 

[rgrock98]

thanks man
Paper 32 was pretty easy

 

[Thought blocker]

thanks man
Paper 32 was pretty easy

u did it?
full marks?
I couldnt to trig question.

 

[rgrock98]

the

u did it?
full marks?
I couldnt to trig question.

Yh i got all of them im pretty sure. Only one im not sure about is the roots to complex equation cause i couldnt cross check it
Do you remember the trig question ?

 

[Thought blocker]

the

Yh i got all of them im pretty sure. Only one im not sure about is the roots to complex equation cause i couldnt cross check it
Do you remember the trig question ?

tan2x - tanx equvivalent to tanxsexc2x

 

[rgrock98]

i did it like this .
Also do u remember what roots u had for the complex number question

 

[Thought blocker]

i did it like this .
Also do u remember what roots u had for the complex number question

u did it like what?
I dont remember.

 

[rgrock98]

wasnt able to upload the image

 

[rgrock98]

https://drive.google.com/open?id=0ByjLCrFu0tDHM3RrbVA0MmhOV1E

 

[Thought blocker]

https://drive.google.com/open?id=0ByjLCrFu0tDHM3RrbVA0MmhOV1E

thanks what about its integration from 0 to pi/6 ?

 

[rgrock98]

for that you just convert the tan2x and tanx to sin and cos; and then use the integral of :- f '(x) / f(x) = ln |f(x) | +c

 

[Thought blocker]

for that you just convert the tan2x and tanx to sin and cos; and then use the integral of :- f '(x) / f(x) = ln |f(x) | +c

why cant we use this : integral of tanx is ln sec x ?

 

[rgrock98]

why cant we use this : integral of tanx is ln sec x ?

uhmm .............because ............. i forgot that XD . But it should give the same result since u derive the formula above by the method i stated