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  1. V

    Chemistry P41 How was it?

    I'm not missing any point. All of what you have said was taught to me, plus it is in the book. I guess you're not giving a second thought about what did I say. Even if it is by just a micrometer to the left, it is still more to the left. From where did you get that? E value for the forward...
  2. V

    Chemistry P41 How was it?

    Yes, I agree. The reaction given might not occur if the condition is not standard. But why do you think? Well, the E value is low. and it should be interpenetrated that 0.3V is the minimum standard in which we can " predict with confidence that the reaction might occur even if the conditions...
  3. V

    Chemistry P41 How was it?

    First of all, the question said to calculate the E⁰ value of the reaction, then HENCE, use that value to suggest whether the position of equilibrium is on the right or the left. Secondly, regarding the concentration values, the reaction might being held under non standard conditions, so position...
  4. V

    Chemistry P41 How was it?

    First of all, the relative values of Kc between reactions with different orders cannot be compared by just matching the numbers, since the units differs!. I.E., Kc, of esterification for example has no units, while the Kc in that question has a unit. This means that you cannot say in that...
  5. V

    Chemistry P41 How was it?

    I If the Cell is not positive, the Forward reaction is NOT FEASIBLE in the first place.
  6. V

    Chemistry P41 How was it?

    OK, this is the case if the reaction goes to completion, but in our case its not. The positive value shows that the reaction can proceed forwardly. The magnitude of that value indicate, how spontaneous then reaction is.
  7. V

    Chemistry P41 How was it?

    If you look at the dissociation of ethanoic acid, for example, the reaction is feasible (and actually it does occur), BUT, the equilibrium still lies more to the left. The Ecell, value was 0.23V, which is very low, so the reaction is not that spontaneous . So it actually lies more to the reactants.
  8. V

    Chemistry P41 How was it?

    I have very strong feeling that this is the right answer. I believe strongly that what you have got, although many did not get it, is right. There is no way of comparing the iron 3 and iron 2, it is EQUILIBRIUM. Meaning you have to compare reactants with reactants, and products with products.
  9. V

    Chemistry P41 How was it?

    I have showed you my steps a little earlier in this thread.
  10. V

    Chemistry P41 How was it?

    Because, they said equal conc of Fe3+ and I- of 100cm3 each were mixed. I.e., equal number of moles of Fe3+ and I-, I think they were just trying to make the question a bit tougher.
  11. V

    Chemistry P41 How was it?

    See, the reactants before equilibrium had the same number of moles, and in the eqn the mol ratio is 1:1. So obviously, I- has to be same as Fe3+. There were nothing of the products in the beginning, so what is produced, has to be in the ratio of 2:1 (between products).
  12. V

    Chemistry P41 How was it?

    Dude, there is a difference between a full equation and equilibrium. There is nothing means half equation when it comes to equilibrium. I mean you have to treat every specie inpendantly.
  13. V

    Chemistry P41 How was it?

    Well, just to make sure. [Fe3+] = 2x10^-4 and [I2] = 1x10^-2 (This is given in the question) I got: [Fe2+] = 2x10^-2 and [I-] = 2x10^-4 reaction is: 2Fe3+ + 2I- ------------> 2Fe2+ + I2 so Kc = ( [Fe2+]^2 x [I2]) / ([Fe2+]^2 x [I-]^2) so Kc = {(2x10^-2)^2 x (1x10^-2)} / { (2x10^-4)^2 x...
  14. V

    Chemistry P41 How was it?

    No, it's not the same as fe3+, [Fe3+]=[I-]. And [Fe2+]= 2[I2] I used mole ratio between reactants. And mole ratio between products.
  15. V

    Chemistry P41 How was it?

    Well, many people I've seen got 25. Still trying to figure out what reasoning did they approach. My Kc was 2.5x10^9. Did anyone get that value also? Or did anyone know somebody got that value?
  16. V

    Chemistry P41 How was it?

    GT around 55. It seems easy, but actually is somehow tricky in some parts.
  17. V

    ---> Physics Paper 4 Past Paper Discussion <---

    The most thing I hate about physics P4 is that some questions are freaking looong, and sometimes 70% of the paper are structured questions and the rest are calculations. Initially, I took physics to get away from writing long responses, and enjoy solving quantitative problems. Now, I feel the...
  18. V

    How was Chemistry P5?

    I don't know about 52, but for 51 I am sure x is 7.
  19. V

    How was Chemistry P5?

    Mmmmm..., I don't think so. X is actually 7, even if you google the formula FeSO4.7H2O you will find that it is the most common hydrated form, if it wasn't the only one.
  20. V

    How was Chemistry P5?

    OK, then you can Google the formula of the second question. You will find the actual value of x.
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