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A level Biology: Post your doubts here!

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5) find out how many division of the eye piece make up one on the stage micrometer
in this diagram there are 40 divisions of eyepiece for 1 division of micrometr
now the chloroplast in the plant cell is 5 divisions of eye piece...
1 of eyepipece = 1/40 of stage micrometer
so 5 of eyepice make 4/40 of stage micrometer.
1 of stage micrometer = .1 mm

so ur answer will be (5/40) * 0.1
 
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When air was bubbled in the medium, thus oxygen was bubbled too and respiration took place, both carbon sugars were uptaken so so far we can't decide which one requires energy (uptaken by active transport) and which is passive. However, when nitrogen was bubbled, the cell could not make respiration thus couldn't generate ATP for active uptake of 6 carbon sugar. As the 3 carbon sugar is a passive process, it doesn't require ATP thus even when cell couldn't make respiration or generate ATP, it was not affected.
 
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12) its tertiary for both bcz only the most complex of structure is altered and that too just a bit... the basic structure of the protein remains unchanged. just the shape changes (tertiary structure) so that it does not fit.
 
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39)
first calculate the mass of the given no. of inviduals of a specie and then find their total energy by multiplying the answer with energy value. i.e.
(no. of species)*(mass)*(energy)
the largest value will be for the first trophic level as they have the highest amount of energy. as we move up the food chain the amount of energy for each level starts decreasin...
best approach is to first write the energy values infront of each option respectively and then arange them in descending order in the options.
 
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39)
first calculate the mass of the given no. of inviduals of a specie and then find their total energy by multiplying the answer with energy value. i.e.
(no. of species)*(mass)*(energy)
the largest value will be for the first trophic level as they have the highest amount of energy. as we move up the food chain the amount of energy for each level starts decreasin...
best approach is to first write the energy values infront of each option respectively and then arange them in descending order in the options.

can u solve it plz
 
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One of the reasons of failure of Measles Eradication programme was that the vaccine needed several boosters. This is a developing country and the idea of several boosters is hard to be applied there. We don't need a combined vaccine for other diseases, the question states for eradication of Measles. A vaccine containing only live measles, I think that this virus is strong so it has to be taken dead. Option D, genetic engineering is expensive and this is a developing country :)
 
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Mit
MaxStudentALevel said: ↑
Hey can anyone explain ON 2008 p1 Q3???
raamish daredevil Irfan1995 ?


Mitochondria has ribosomes 70 s and circular DNA as a prokaryote so it didn't lose this feature. A prokaryotic cell doesn't even have ER ( no membrane bound organelles are present) However, a prokaryotic cell has a cell wall and mitochondria doesn't have one so it's the right answer.
 
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