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nope
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A level Biology: Post your doubts here!
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nope
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http://papers.xtremepapers.com/CIE/...nd AS Level/Biology (9700)/9700_w11_qp_12.pdf
Q5(B), 20(C) , 23(C)
Someone helppp ! Yaar koi help karoooo !
Q5(B), 20(C) , 23(C)
Someone helppp ! Yaar koi help karoooo !
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http://papers.xtremepapers.com/CIE/...nd AS Level/Biology (9700)/9700_s12_qp_11.pdf
Q16(C), 39(C) HELPP ! Could someone explain?
Q16(C), 39(C) HELPP ! Could someone explain?
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5) find out how many division of the eye piece make up one on the stage micrometer
in this diagram there are 40 divisions of eyepiece for 1 division of micrometr
now the chloroplast in the plant cell is 5 divisions of eye piece...
1 of eyepipece = 1/40 of stage micrometer
so 5 of eyepice make 4/40 of stage micrometer.
1 of stage micrometer = .1 mm
so ur answer will be (5/40) * 0.1
When air was bubbled in the medium, thus oxygen was bubbled too and respiration took place, both carbon sugars were uptaken so so far we can't decide which one requires energy (uptaken by active transport) and which is passive. However, when nitrogen was bubbled, the cell could not make respiration thus couldn't generate ATP for active uptake of 6 carbon sugar. As the 3 carbon sugar is a passive process, it doesn't require ATP thus even when cell couldn't make respiration or generate ATP, it was not affected.
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12) its tertiary for both bcz only the most complex of structure is altered and that too just a bit... the basic structure of the protein remains unchanged. just the shape changes (tertiary structure) so that it does not fit.
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i don't get you.
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39)
first calculate the mass of the given no. of inviduals of a specie and then find their total energy by multiplying the answer with energy value. i.e.
(no. of species)*(mass)*(energy)
the largest value will be for the first trophic level as they have the highest amount of energy. as we move up the food chain the amount of energy for each level starts decreasin...
best approach is to first write the energy values infront of each option respectively and then arange them in descending order in the options.
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20)
look there is a double stranded DNA which has 12000 bases. if we take one strand - bcz one strand is needed to make a polypeptide - it means 6000 bases are present. then divide the 6000 by 3 bcz every 3 bases for one amino acid. as a result we get 2000 amino acids for that polypeptide.
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can u solve it plz
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R = 1000 (just multiply all the three values)
S = 100
T = 1.8
U = 450 000
from largest to smallest energy values: -
U > R > S > T
There's the BCG vaccine. Although it's not 100% effective, it's the best we've got so far.
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so TB is a viral disease and vaccine is used to combat it??
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One of the reasons of failure of Measles Eradication programme was that the vaccine needed several boosters. This is a developing country and the idea of several boosters is hard to be applied there. We don't need a combined vaccine for other diseases, the question states for eradication of Measles. A vaccine containing only live measles, I think that this virus is strong so it has to be taken dead. Option D, genetic engineering is expensive and this is a developing country
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Mit
Mitochondria has ribosomes 70 s and circular DNA as a prokaryote so it didn't lose this feature. A prokaryotic cell doesn't even have ER ( no membrane bound organelles are present) However, a prokaryotic cell has a cell wall and mitochondria doesn't have one so it's the right answer.
Mitochondria has ribosomes 70 s and circular DNA as a prokaryote so it didn't lose this feature. A prokaryotic cell doesn't even have ER ( no membrane bound organelles are present) However, a prokaryotic cell has a cell wall and mitochondria doesn't have one so it's the right answer.
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measure the size of the nucleas with a scale.Convert into micrometer. magnification is already given. Use the formula Magnification=Size of the image/Size of the specimen