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does anyone have good summarized bio AS and A level notes, really need them
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i know but i need summarizing points for it, this will help me alot overcoming my problems in this sectionPotometer is not that difficult....just go through the book once, i think you will understand it....and i have seen a potometer related question in p2..so there's a chance
At PCT , urea is some urea is absorbed due to its small size....not all of them.....so at DCT and collecting duct, almost all of the water is absorbed, leaving urea and other waste products....so, its concentration increases....why does concentration of urea increase in distal collecting tubule and collecting duct????
Your WelcomeThank u so muchhh nabil, mehria and salik dat realy helped! So nyc of u
First find Out What One unit on Graticule represents.
It says the Slide has division of 0.1 mm, which are equivalent to 50 on Graticule. So 1 division on Graticule is 0.1/50 =0.02 mm.
Now look at Diagram One, Take the pollen which grows Straight (parallel to scale), Then place a ruler and see the increase in its size after 4 hours, which turns out to be from 25-35 which is 10 Graticule units. the actual Increase is 10 * 0.02=0.2 mm , But this is in 4 Hours. the question asks for One Hour , then divide this value by 4 which gives 0.05 mm = 5 Micrometer Per Hour.
Hope i Helped !
Here is the calculation,from 1st diagram
50 eyepiece divisions=0.1 stage
1 EP=0.1/50 stage
Convert it to micrometer,
1EP=0.1/50 multiplied by 1000, which is 2 micrometer.
Now from 2nd diagram,
The increment in 4 hours is 10 division
So 1 division of EP=2
10 division of EP=2 into 10
=20
so in 4 hours, there is increment of 20 micrometer
In 1 hour=20/4
=5
So the answer is A.
No ProblemThankyou both of you, you're awesome!
Q4 C (i):- It is a competitive inhibitor which binds to active site reversibly, But as the concentration of Substrate increase we see see more frequent collision between substrate and enzyme rather than inhibitor and enzyme, this reduces the effect Of inhibitor.Help please !
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_s13_qp_23.pdf
Q4 C (i) and Q5 (d)
Q4 C (i):- It is a competitive inhibitor which binds to active site reversibly, But as the concentration of Substrate increase we see see more frequent collision between substrate and enzyme rather than inhibitor and enzyme, this reduces the effect Of inhibitor.
So the curve would be lower than normal at start but Vmax reached at higher substrate concentrations.
This might help too.. http://cnx.org/content/m44429/latest/Figure_06_05_04.jpg
I will give a try to Question 5(d) (correct me if i m wrong plz)
I MPF Doesnot break Down, There would be Too many Prophase At the same time, which would cause uncontrolled Mitosis, (but wont form Tumors, because still Anaphase and rest of phase go by Normal Time ) And this would also Disturb the cell Cycle (causing shortened S Phase)
You r WelcomeThanks a bunch for the Graph
and 5(d) this is correct but they say said that there aslo maybe a risk of tumour ..can u explain me more ?
You r Welcome
Risk of tumor? Where do they say that?
I dont Think there would be Any Tumors???
Ohh.. In Ms it says I (ignore) ref to any tumors!!In M.s only check
Ohh.. In Ms it says I (ignore) ref to any tumors!!
In M.s
"ignore (risk of), tumour formation / cancerous growth "
Q6 :- (A)The question asks for greatest mass of Non- Reducing sugar, which means the difference between Before and after Hydrolysis must be greatest, which is in A!
Q11:-(A) Triglycrides dont have Hydrogen bonds, So Not D.Cellulose has Hydrogen bonds so Not B either. Collagen is helical in nature (not branched) so not C. Ans is A
Q14:-(C) If the inhibitor binds to E-S complex then active site doesnt change shape. so 1 is wrong. and With inhibitor V(max) never increases, so Ans is C!
Q25:-(B)5 is wrong because they are in Dry conditions, So only ans is B or C. Fewer Stomata would reduce gas exchange so the ans is B.
Q35:-(D) Emphysema has no Link with Atheroma(cant be C). Tar causes more Mucus (if he stopped smoking, so A is wrong).Stopped smoking reduces inflamation to lung tissues so Macrophage decrease. Only other option is D.
Q38:-(A) Vaccine dont only work against viruses, bcz there r vaccines for TB as well,, so only option without 4 is A.
Hope i Helped . if u need detailed explanation do let me Know!
Q14:-THANKS A LOT
June -2011 (v1)
but I still didn't get Q 14 :/
June 2012 (v2)Paper 1 doubts
June 2012 (v2) ----> Q10 and Q27
Nov 2012 (v2) ----> Q1 - Q17 -Q15 -Q21 -Q24 -Q34 - Q38
Nov 2012 (v3) ---->Q30,Q36 and Q39
Help is appreciated
Paper 1 doubts
June 2012 (v2) ----> Q10 and Q27
Nov 2012 (v2) ----> Q1 - Q17 -Q15 -Q21 -Q24 -Q34 - Q38
Nov 2012 (v3) ---->Q30,Q36 and Q39
Help is appreciated
Q30) It says Mucus is increased which causes More exocytosis in Goblet cell So option 2 is wrong. Only Ans without 2 is B.Paper 1 doubts
June 2012 (v2) ----> Q10 and Q27
Nov 2012 (v2) ----> Q1 - Q17 -Q15 -Q21 -Q24 -Q34 - Q38
Nov 2012 (v3) ---->Q30,Q36 and Q39
Help is appreciated
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