A level mechanics HELP!!!!!

[Mujjix113]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_qp_41.pdf
guys question number 6 part 1 when resolving for X direction and Y direction plzz tell me why we dont include the 5 newtons in the y direction because usually we do...

 

[snipex]

lol man read the question properly these forces are nt vertical but horizontal and these foreces represent direction of movement like front or back or right or left

 

[Mujjix113]

lol man read the question properly these forces are nt vertical but horizontal and these foreces represent direction of movement like front or back or right or left

either way we solve resolve the forces in X and Y direction because p is in equilibrium

 

[snipex]

yup and then get f by simultaneos eq

 

[Mujjix113]

but the thing is when i resolve for the X direction i get a correct answer that part is good but when i resolve for the Y direction including the weight of p i get a wrong answer but then i checked the marking scheme and find out that they haven't even added the weight for the Y direction.. that is the most confusing part cuz usually when the block or particle is in equilibrum and has a mass i usually take the weight as well

 

[snipex]

as I told you before these ar horizontal forces nt vertical, in other wrods you dont add the weight becaue forces in y direrion in this question moves object forward and backward nt up and down, it like movin box forward without raisng it up, simply the weight is perpindicular to these forces

 

[Mujjix113]

as I told you before these ar horizontal forces nt vertical, in other wrods you dont add the weight becaue forces in y direrion in this question moves object forward and backward nt up and down, it like movin box forward without raisng it up, simply the weight is perpindicular to these forces

Dude look at the marking scheme they are giving a mark just for resolving in the X and Y direction... what you are saying is only restricted to the X direction

 

[snipex]

huh am sayin dont iclude the weight in your calculations :/

 

[Mujjix113]

huh am sayin dont iclude the weight in your calculations :/

can u show me how u did it?

 

[snipex]

forget that you have a weight and treat it as normal resolving question you will get the ans

 

[Mujjix113]

forget that you have a weight and treat it as normal resolving question you will get the ans

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_43.pdf question 5

 

[Mujjix113]

forget that you have a weight and treat it as normal resolving question you will get the ans

take a look at these questions they are all including the weight in their Y component https://googledrive.com/host/0B1ZiqBksUHNYdG9SOEVLaTVSYUE/CH4.pdf

 

[snipex]

1)resolve all forces, 5sintheta will be equal to 4.8 so cancel each other
2)5costheta+6.1 =7.5
3)since the speed is constant means Ef=0 so force applied is equal to frictional force

 

[snipex]

take a look at these questions they are all including the weight in their Y component https://googledrive.com/host/0B1ZiqBksUHNYdG9SOEVLaTVSYUE/CH4.pdf

these questions the forces are parallel to weight

 

[Mujjix113]

the past paper question u just solved with the frictional force if u do part 2 u r supposed to take the weight

 

[snipex]

in part 2 yes