okWith the application booklet I got some main ideas and then got to understand everything much better through answering past papers and then checking the mark-schemes...
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okWith the application booklet I got some main ideas and then got to understand everything much better through answering past papers and then checking the mark-schemes...
Oscillations are damped by eddy currents. These currents dissipate energy in the form of heat to surrounding as E=IVt. energy comes from the oscillations of the system. As, energy is lost gradually, amplitude also decreases gradually because amplitude depends on energy...oct/nov 2006 question 5(b)
could anyone please explain this for me ?
because we assume that planets are of uniform density and its mass is concentrated at its centre. (i am not sure though_well why newtons law apply to planets even though they r nt point masses......ms says radius much smaller than separation.........i dint unerstand this....wen performing calculations we are taking distance between centres of two planets.......isnt it?
read applications from International A/As level Physics by hodder education. Writers: Chris Mee,mike crundell
5c(i)please answer my question too
ver u see mean power....use RMS valueswhat value of voltage do we use while calculating the mean power through a resistor. the rms value or the peak value and why?
because that Irms=Io/2^1/2 is only applicable to sine curve waves as it was derived from I=Iosinwt.I have another doubt
please explain if you dont mind
June 2004 question 5 d (i) and (ii)
Why is the r.m.s value the same?
for square Irms= peak value and for sawtooth Irms=Io/3^1/2I have another doubt
please explain if you dont mind
June 2004 question 5 d (i) and (ii)
Why is the r.m.s value the same?
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