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12-4125oooo Hz for carrier frequency... btw how did you find frequency of signal wave???
8*10^-6 s
1/8*10^-6
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12-4125oooo Hz for carrier frequency... btw how did you find frequency of signal wave???
why 12 - 4???:S12-4
8*10^-6 s
1/8*10^-6
Assalamoalaikum wr wbFrom the application booklet,
"There is a continuous distribution of wavelengths with a
sharp cut-off at short wavelength and also a series of high-intensity spikes that are characteristic of the
target material."
I dont get the difference between the "sharp cut-offs" and the "high intensity peaks" since according to the text, they are different things! :S
sharp cut-off at short wavelength is due towhen e give all their energy to photon and this is min wavelenghtFrom the application booklet,
"There is a continuous distribution of wavelengths with a
sharp cut-off at short wavelength and also a series of high-intensity spikes that are characteristic of the
target material."
I dont get the difference between the "sharp cut-offs" and the "high intensity peaks" since according to the text, they are different things! :S
link plz?Assalamoalaikum wr wb
Check the notes from XPFMember...that has that graph and the answers to the different features of the graph...may be that'll help..
I know that, but I mean I cant differentiate between them on the graph!sharp cut-off at short wavelength is due towhen e give all their energy to photon and this is min wavelenght
whereas "high intensity peaks are when e are excited n then deexcited hope u understood the d/f
http://www.xtremepapers.com/communi...-2012-last-minute-revision.14313/#post-216441link plz?
I know that, but I mean I cant differentiate between them on the graph!
watch thisFrom the application booklet,
"There is a continuous distribution of wavelengths with a
sharp cut-off at short wavelength and also a series of high-intensity spikes that are characteristic of the
target material."
I dont get the difference between the "sharp cut-offs" and the "high intensity peaks" since according to the text, they are different things! :S
Aoa wr wb!link plz?
I know that, but I mean I cant differentiate between them on the graph!
watch this
Definitely helped, Thank you for the clarification! Jazakum allahu khairan!
JazakAllah khairen....it's only that i understood that sharp peakswatch this
wa eyyakum!Definitely helped, Thank you for the clarification! Jazakum allahu khairan!
JazakAllah khairen....it's only that i understood that sharp peaks
wa eyyakum!
wa eyyakum!Definitely helped, Thank you for the clarification! Jazakum allahu khairan!
plz explain wo9 p41 q 6 b iJazakAllah khairen....it's only that i understood that sharp peaks
wa eyyakum!
Assalamoalaikum wr wb once again..plz explain wo9 p41 q 6 b i
and q7 b i n ii
walkum aslam.Assalamoalaikum wr wb once again..
wel this is what i understand...
usse right hand grip rule to get the field direction ...it would be anticlockwise...(circular)
so the points gonna be to the left of that current...
wa eyyakum..walkum aslam.
thanx nd wht abt that alternating voltage. how to draw on that graph????
jazak Allah
i still didnt get it.. can you put a sketch of it over here...wa eyyakum..
half wave rectification...
with height reduced i think...[dont rremember why..if u get to know..lemme know tooo..]
and in one it'll be only the positive part and no negative part...'
in the second it'll be only the negative part not the positve...u can see this when yo look in the diagram and see how they're gonna work..as the input is ac..it'll be one time up one is positive..and then negative..and goes on..
btw need help with frequency modulation plzz...
and also i dont get the sidebands part in the amplitude modulation...!!
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