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Then post more hard questions for practice please
Half wave Rectifier:- http://en.wikipedia.org/wiki/File:Halfwave.rectifier.en.svg
A Analogue to digital converter is used where samples are taken at certain intervals of time i.e sampling rates to convert the decimal number into binary digits made of a certain number of bits.
i asked across diode!!!Then post more hard questions for practice please
Half wave Rectifier:- http://en.wikipedia.org/wiki/File:Halfwave.rectifier.en.svg
Full wave Rectifier:- http://en.wikipedia.org/wiki/File:Gratz.rectifier.en.svg
Then just flip your monitor upside down
The shape of magnetic flux graph would be same as the shape of current graph. So, at first, the gradient is maximum and positive giving rise to a large negative emf - the gradient decreases to zero in the end of first part, so the emf goes from that max. value to zero. You can't draw a straight line because then you can't show that the decrease to zero is gradual.please make some brief elaboration on the first part of the emf of the graph... why is it somehow as a sine graph rather than a cosine graph? why couldnt it be a straight line sloping downwards?
How do we know if the rate of decrease is constant or the rate of decrease is increasing/decreasing? Will appreciate some interpretation
Have some problems getting this clear... The gradient of the current graph looks undefined at the beginning? tangent to that point is vertical? means emf shouldnt touch the axis?
Slightly less than vertical, which means that there's a large emf. My diagram shows both graphs being compared. See it again with the explanation I gave above.
answers?
thats the problem , i cant seem to agree with your explanation.
yeah i also dont agree with the explanation......
If you see the graph of current, you will see that current becomes constant just a little time before the start of the second phase. You need to show that the emf goes from a specific maximum value to zero - you can't show it the other way round. I really feel there is no more to say here.
You seem very confident, yet having problems interpreting the problem
I am agreeing with you, did you find anything yet ?
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