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A2 Physics | Questions and Doubts [Post Here]

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AsA

As the other thread is getting filled with AS questions. Use this one for asking asking A2 related questions.
 
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Can anyone help me with these questions please ???o_O
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w07_qp_4.pdf

Q1 b(iii)
Q2 b(ii) 2
Q4 c(ii)
Q7 (c)
Q2 bii) W=mg
mg / gravitational force calculated in b( i)
=> (4*1.66*10^-27) * 9.81 / (2.49*10^-46)
=> 2.6*10^20
Q6 bi) The current in one loop pf wire produces magnetic field which is perpendicular to the current in the second loop. According to the Newton's Law, their is force of attraction and hence the separation of the loops in the coil decreases.
Q7 c) N(Ba) / N(Kr) = No e^-decay constant *t / No e^-decay constant *t
=> 8/1 = [e^ (-6.42*10^-4 * t) ] / [e^(-0.231t)]
Take Ln on both sides nd solve for t=9.0 sec
 
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Q2 bii) W=mg
mg / gravitational force calculated in b( i)
=> (4*1.66*10^-27) * 9.81 / (2.49*10^-46)
=> 2.6*10^20
Q6 bi) The current in one loop pf wire produces magnetic field which is perpendicular to the current in the second loop. According to the Newton's Law, their is force of attraction and hence the separation of the loops in the coil decreases.
Q7 c) N(Ba) / N(Kr) = No e^-decay constant *t / No e^-decay constant *t
=> 8/1 = [e^ (-6.42*10^-4 * t) ] / [e^(-0.231t)]
Take Ln on both sides nd solve for t=9.0 sec
Guys i think the 1stpart is this ....
U need to know at bottom part,the fbd is like this tension-weight=centripetral force
so first up find the spring constant,,f=kx,,,k=5/1.8
tension=centripetraal force +weight
2.78(L-13)=mrw^2+5
L=17.2cm
 
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Help in op-amp

I think it looks like this for thhe 1st question.Confirm me if thats the answer.If It IS i will explain it to u....
 

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periyasamy
Thats the markscheme answer :
graph: square wave
correct cross-over points where V2 = V1
amplitude 5 V
correct polarity (positive at t = 0)
So your answer is right , Plus dont forget plz to explain the second question too :)
 
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