- Messages
- 872
- Reaction score
- 894
- Points
- 103
Does anybody have the Summer 1997 past papers? Well I really don't understand question number 5 from paper 2. Could someone please explain it to me
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Tell me the topic from which it is from or just post the question! I have a Classified Ad. Maths past papers book which has summer 97 questions!Does anybody have the Summer 1997 past papers? Well I really don't understand question number 5 from paper 2. Could someone please explain it to me
Does anybody have the Summer 1997 past papers? Well I really don't understand question number 5 from paper 2. Could someone please explain it to me
Its in topic 7: logarithmic functions, and is question number 24 (a) in the classified past papers' book from 1996 to 2008Tell me the topic from which it is from or just post the question! I have a Classified Ad. Maths past papers book which has summer 97 questions!
Is this the question: (i) lg x + lg[5(x+1)] = 2Its in topic 7: logarithmic functions, and is question number 24 (a) in the classified past papers' book from 1996 to 2008
If yes, then here's the solution:Is this the question: (i) lg x + lg[5(x+1)] = 2
(ii) 3^(y+1)=0.45
No no. That's part b! I don't get part a. Here's the question:Is this the question: (i) lg x + lg[5(x+1)] = 2
(ii) 3^(y+1)=0.45
Nah, you noted the wrong question.No no. That's part b! I don't get part a. Here's the question:
An object is heated in an oven until it reaches a temperature of X degrees Celsius. It is then allowed to cool. Its temperaure, (theta) degrees celsius, when it has been cooling for t minutes, is givwen by the equation (theta)= 18 + 62 e^-t/x
Find
ii) the value of X
ii) the value of (theta when t = 16
iii) the value of t when (theta)= 48
1v) the rate which (theta) is decreasing when t= 16
I don't understand why there's an x under t as the exponent, and according to the marking scheme of part ii, the value of that x is equal to 8 whereas no part of the question gives that away. The answer to part i is 80 degrees celsius and that, i get how. What particularly confuses me is the presence of the two Xs
Nah, you noted the wrong question.
The equation is: 18 + 62 e^-t/8
There's some sort of misprinting.....Check question number 19 in Miscellaneous Exercise 3 in "New Additional Mathematics" book by Ho Soo Thong and Khor Nyak Hiong! It states the correct question.
By the way from where did u get the Marking Scheme of 1997??????????
Snowysangel and scouserlfc: Your help needed in this question.
Given that n(E)=23, n(A ∩ B)=x, n(A)=y, n(B)=2y and n(A' ∩ B')=7, find the least possible value of y. The answer is 6. How to do it????
I hate sets,Inshaallah will solve tomorrow if no one else touches it
Yes, from the book!Is this question from the book man because i cant this thing right now but later when im not on the computer ! if not wait ill try my best
"New Additional Mathematics" book by Ho Soo Thong and Khor Nyak HiongUgh I haven't started with sets in add math, I was hoping it would be as easy as it is in math guess I was wrong
Well I don't exactly know how to solve it, but I do know that xy = 2y if y is equal to 6. B is most likely to be the subset of A, but that would leave out x and a simultaneous equation couldn't be formed :S
Give me a day or two and I'll try and come up with a solution, but yeah, if you found this in a book, could you give us the name
Snowysangel and scouserlfc: Your help needed in this question.
Given that n(E)=23, n(A ∩ B)=x, n(A)=y, n(B)=2y and n(A' ∩ B')=7, find the least possible value of y. The answer is 6. How to do it????
Note: n(E) is for the universal set.
n(AUB)=23-7
n(A)+n(B)-n(A ∩ B)=16
y+2y-x=16
3y=16+x
y = (16+x)/3
to find minimum value of y,
x must be minimum also,
but x=0, y =16/3
and x=1, y=17/3
both y is not integer, so can't be the answer
so, x=2, y=18/3
y=6
Wait mate but how can u just use values on ur own is this a method ??
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now