AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

[Bai fong]

anyway h is 2 , h is 1 is not good

 

[Hamnah Zahoor]

anyway h is 2 , h is 1 is not good

agreed.

 

[A*****]

binomial, a = 3
k<9 and k = 11

a = 8000 , r = 1.02

h= 1 k =22

a = 7 b= -4 , for no solution k > 7 , and k < 3

x = 146 , 323
range for which 2cos > -3sin , 0 >x> 146

I think h and k didn't had these values

 

[ThePacifics]

yeh they were def not 1 and 22. i dont remember but the calculation wasnt tough it was straightforward.

 

[Abdi Ali]

I got h as 2 and K as 36

 

[Abdi Ali]

My volume was 32/3 pi

 

[karen0009]

what was dot product angle

 

[Abdi Ali]

I'm not sure about the vectors one but I got -22 , it's probably wrong

 

[Abdi Ali]

My angle was 137.8

 

[karen0009]

what about area of shaded region?

 

[Abdi Ali]

That one I didn't quite figure out

 

[ThePacifics]

mine was 104/3 pi

 

[Julius696969]

Shaded area was 32.1

 

[ThePacifics]

i probably took the last one wrong i just realized oof sorrysjjsjs

 

[A*****]

I got h as 2 and K as 36

Same

 

[A*****]

My angle was around 87°...I don't remember the exact one

 

[PhantomFlash]

Does anyone remember the y=x question?

 

[ThePacifics]

Does anyone remember the y=x question?

p and q were 2 and 6. i just found the points and showed their gradients were same to prove y=x idk if i'll get ecf for this method

 

[A*****]

p and q were 2 and 6. i just found the points and showed their gradients were same to prove y=x idk if i'll get ecf for this method

Yes but I took it further to find the equations of both tangents and then their point of intersection by solving them simultaneously. x and y coordinate was same so I wrote hence, it is proved.

 

[ThePacifics]

you mean i can still score in this one?