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Atleast partial credit will be given as far as I thinkyou mean i can still score in this one?
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Atleast partial credit will be given as far as I thinkyou mean i can still score in this one?
Wait wait...the gradients were not samep and q were 2 and 6. i just found the points and showed their gradients were same to prove y=x idk if i'll get ecf for this method
they cant be the same... the gradient of one should be the -ve reverse of the other.... and yes their points of intersection meet on the line y=x , which when you equate both, gives you an x that equals to the yp and q were 2 and 6. i just found the points and showed their gradients were same to prove y=x idk if i'll get ecf for this method
waitt wasnt it k>11 and k<3??binomial, a = 3
k<9 and k = 11
a = 8000 , r = 1.02
h= 1 k =22
a = 7 b= -4 , for no solution k > 7 , and k < 3
x = 146 , 323
range for which 2cos > -3sin , 0 >x> 146
12For geometric sequence question was n=12 or n=13
I got that toowaitt wasnt it k>11 and k<3??
The original paper 12 was leaked so Cambridge sent out replacement papers, that's why it was dark yellow.Guys my paper was dark yellow? is this normal?
wasnt it k>9 as the inequality sign reversed cuz of dividing it by a negative value?binomial, a = 3
k<9 and k = 11
a = 8000 , r = 1.02
h= 1 k =22
a = 7 b= -4 , for no solution k > 7 , and k < 3
x = 146 , 323
range for which 2cos > -3sin , 0 >x> 146
it was n=12, tricky cuz in the 2018 f/m paper n was 61 daysFor geometric sequence question was n=12 or n=13
but wasn't it ">" in the beginning so after you divide by the negative value it turns to "<"?wasnt it k>9 as the inequality sign reversed cuz of dividing it by a negative value?
I dont remember exactly but the question said that the curve didnt intersect right?but wasn't it ">" in the beginning so after you divide by the negative value it turns to "<"?
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