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Mine went great too alhamdullilah.
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Why are we assuming that the initial and final velocity are 0?? It dusn't say it is dropped from rest?
dude, only A was correct............................For this velocity-time graph :
View attachment 13137
Whats the displacement-time graph? My answer was B but displacement is never negative although later it was moving in opposite direction ryt?
View attachment 13136
:O Wt ws A?dude, only A was correct............................
it was a curve begining from s=0 and ending at s=0 also.............:O Wt ws A?
Yah dude how can that be ryt when Displacement becomes zero two times , Look at the velocity time graph , it goes to max displacement then 0 and then max displacement in opposite direction and then zero...it was a curve begining from s=0 and ending at s=0 also.............
Your right , A was the correct answerit was a curve begining from s=0 and ending at s=0 also.............
variant 1...it was ok...did sm mstakes thoughoh great!
so u gave which variant? 12?
hmmm wasnt it an LDR and a variable resistor??btw for variant 1 ppl...there was a question in da last questions which included da LDR and a fixd resistor in which voltmeter was parallel 2 da fxd resistor and not 2 da LDR...then they said 4 a high voltage what should da conditions be of light 4 resistor and ldr......wat was da answer :S
hmmm wasnt it an LDR and a variable resistor??
i wrote A as the answer : high light intensity, high resistance for second column
not sure though:/
might be sory dont remember :S but mee too Ahmmm wasnt it an LDR and a variable resistor??
i wrote A as the answer : high light intensity, high resistance for second column
not sure though:/
hey i've s0me questions on physics too, they are
may/jun 02 Q13 in the attachment below and
oct/nov 03 Q14
i just don't get which distance to take between the two forces to calculate the torque
thXx,,,it really helpedfor question 13 ... for finding torque we always have to take the perpendicular distance between the two forces. So taking it needs to find it out.
Do so by using the theory of right angled triangle.
sin50 = per./hyp.
sin50 = per./0.30
solve to get the perpendicular distance here
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