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its no . 29 >>>http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf
btw help me with no . 17 also > http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdf
thanks
mcq 29: power are same, so use P=V^2/R
cancel powers nd then (12^2)/6^2 = Rx/Ry u will solve to get 4...
mcq 17: electrical to light is only 7J hence...7/(93+7) * 100= 7 %