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If you write down the equations of motion for the two objects (barrel coming down and man going up), you get:
Barrel:
Tension = 120g - 120 * acceleration
Tension = 1200 - 120a
Man:
Tension = 80g + 80a
Tension = 800 + 80a
Equating the two,
1200 - 120a = 800 + 80a
400 = 200a
a = 2 ms^-2.
Since the two objects both start from rest and have the same accelerations (they are connected by the string, so if one moves a distance x, so does the other, in the same time interval), the mans head will be in line with the bottom of the barrel after travelling 9 meters. Therefore,
u = 0 ms^-1 , a = 2 ms^-2 , s = 9m:
v^2 = 0 + 2 * 2 * 9
v^2 = 36
v = 6 ms^-1 = A
Hope this helped!
Good Luck for all your exams!
understood it!thanks alot and best of luck for your exams too!!