AS Physics P1 MCQs Preparation Thread.

[omg]

here you go love

THANKYOU
are u havin ms of 1997 and 1998??
i just found those pprs bt dun hv the ms :/

 

[hmlahori]

People needs loads of help here! thanks!

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s07_qp_1.pdf
http://www.xtremepapers.com/papers/...A and AS Level/Physics (9702)/9702_s07_er.pdf
Q8 How do we solve this question. tried many ways but dont get correct answer.
Q10 i'm getting answer D but the correct is B. How?
Q20 How do we know its answer?
Q23 Why cant the answer be A?
Q40 How do we know its answer. the mark scheme says something about q/m ratio, that it should be lowest. But what is q/m ratio?


http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_1.pdf
http://www.xtremepapers.com/papers/...A and AS Level/Physics (9702)/9702_s08_er.pdf
Q6 Why is there no change in speed?
Q13 and Q14 how do we find there answers always get these type of questions wrong is there a particular method to solve them?
Q22 Why isnt the answer C? And wat is the difference btw elastic limit and limit of proportionality?
Q24 how do we solve this. i get '8E' which is not even one of the options!


http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s09_qp_1.pdf
http://www.xtremepapers.com/papers/...A and AS Level/Physics (9702)/9702_s09_er.pdf
Q 10, 15 & 18. How to solve them?
Q19 I think answer should be D. cant be B or C. btw aluminium and steel. steel will sustain largest deformation since its an alloy, mixture of metals, so will be stronger than aluminum alone rite?

 

[omg]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w04_qp_1.pdf
q. 20 plsss any1

 

[USMAN Sheikh]

If the line was fully straight the velocity would be zero because the gradient would be zero.

lesco thanks alot man u r doing a great job few more questions for u kindly solve them pls
q 14 and 36 of june 11 variant 11
q 26 28 36 of november 11 variant 11

 

[bloody_mary]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_1.pdf q-14

Can anyone help me with these questions??View attachment 12303View attachment 12304View attachment 12305

for question 14


therefore h*f + Wa (since it is perpendicular distance between force and pivot)
and the 2Wa part comes from using top of ladder (part resting on wall) as pivot because if distance between pivot and force is 0 then there is no moment

so answer is A = Wa+hf = 2wa

 

[bloody_mary]

THANKYOU
are u havin ms of 1997 and 1998??
i just found those pprs bt dun hv the ms :/

nope but can you share them please?

 

[bloody_mary]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_1.pdf q-14
and
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w08_qp_1.pdf
q-31!
plss helppppppppppppp

question 31
R=ϱl/a and R= V/I

so v/I =ϱl/a which gives I= av/ϱl and area of wire is π*r^2
both wires are of same material so ϱ is constant

so current in P = π*1^2 V/ϱl

and current in Q = π*(0.5)^2 V/ϱl (notice it says diameter)

then divide by each other and you should get 4/1 which is D

 

[SalamH]

THANKYOU
are u havin ms of 1997 and 1998??
i just found those pprs bt dun hv the ms :/

cud u post d pprs pls n where did you find them

 

[bloody_mary]

People needs loads of help here! thanks!

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_er.pdf
Q8 How do we solve this question. tried many ways but dont get correct answer.
Q10 i'm getting answer D but the correct is B. How?
Q20 How do we know its answer?
Q23 Why cant the answer be A?
Q40 How do we know its answer. the mark scheme says something about q/m ratio, that it should be lowest. But what is q/m ratio?
quote]

Q8
ok first of all find time taken to fall 30m as they only want last 10m
so s=ut+at^2/2 30=9.81*t^2/2 t=2.47

now use t to find v after falling 2.47s (this will be the u of last 10m) v=u+at
v=9.81*2.47 =24.2

then again use s=ut+at^2/2 using s as 10 so 10=24.2*2.47+9.81*2.47^2/2 which gives 0.38s

Q10 i am guessing
that it is B because if you look at the graph p2 is negative and to find average you add the 2 things and divide by 2
so negative p2 gives +p2 so p1+p2 is correct

Q20
you just have to think about this for a while

Q23
because speed isn't max at that point it actually stops to change direction
other answers are incorrect except D

Q40
no clue at all :S

 

[fathimaash]

anyone having O.N.01 paper and MS pls post...

 

[bloody_mary]

anyone having O.N.01 paper and MS pls post...

 

[xxfarhaxx]

Q- 18, 21, 25, 30-how can da ans is C..shudnt it b A or B??
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w06_qp_1.pdf
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w06_ms_1.pdf

 

[bloody_mary]

People needs loads of help here! thanks!

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_er.pdf
Q6 Why is there no change in speed?
Q13 and Q14 how do we find there answers always get these type of questions wrong is there a particular method to solve them?
Q22 Why isnt the answer C? And wat is the difference btw elastic limit and limit of proportionality?
Q24 how do we solve this. i get '8E' which is not even one of the options!

Q6
this question is about circular motion ie centripetal force and when an object is in circular motion it is speed is constant unlike velocity as direction always changes and so does accn so answer is C

Q13
whenever an object is in equlibrium its triangle of forces should not have any 2 forces pointing towards each other they must flow like a cycle

Q14 i did before in this post just go back

Q22
elastic limit is the limit where if more load is added on a material it starts undergoing plastic deformation
limit of proportionality is region where extension in proportional to force which is the staright part of graph
and answer is B because it has not undergone plastic deformation yet if it has then there would have been a permanent extension at bottom of graph

Q24
answer is supposedly C :S

 

[USMAN Sheikh]

Q6
this question is about circular motion ie centripetal force and when an object is in circular motion it is speed is constant unlike velocity as direction always changes and so does accn so answer is C

Q13
whenever an object is in equlibrium its triangle of forces should not have any 2 forces pointing towards each other they must flow like a cycle

Q14 i did before in this post just go back

Q22
elastic limit is the limit where if more load is added on a material it starts undergoing plastic deformation
limit of proportionality is region where extension in proportional to force which is the staright part of graph
and answer is B because it has not undergone plastic deformation yet if it has then there would have been a permanent extension at bottom of graph

Q24
answer is supposedly C :S

help me out too pls

 

[omg]

cud u post d pprs pls n where did you find them

i found dm on ma bookshelf
dun hv the link :/

 

[floral123]

Q- 18, 21, 25, 30-how can da ans is C..shudnt it b A or B??
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_ms_1.pdf

q:18
total input power required is 4MW/0.8 = 5 MW.
P= VI
I= 5MW/25 KV = 200 A.....ANS!

 

[omg]

nope but can you share them please?

how 2? :/
i hv a hard copy

 

[XPFMember]

AsSalamoAlaikum Wr Wb!

Here's a comment from the examiner:

Since there is considerable time pressure on candidates to complete 40 questions within the time limit of one hour, there is pressure to ignore the checking process. It is all the more important, therefore, to read the question carefully in the first place. In particular, when answering verbal questions, candidates should check all four options, rather than looking at just one or two of them. This is because one option may look correct, but a further option may trigger a different thought for the candidate; something that may not have been thought about when reading the first, apparently correct, option. Powers of t en are a source of many errors with numerical questions. These arise not just by using a calculator incorrectly, but also with the metric system prefixes.

Candidates must use space on the paper for working: on leaving the examination room their paper should be covered with writing.

Source: Nov:2008 Examiner Report

 

[xxfarhaxx]

q:18
total input power required is 4MW/0.8 = 5 MW.
P= VI
I= 5MW/25 KV = 200 A.....ANS!

wel shoundt u convrt thm to their standad units...i thnk if u do it tat way u gt it as B......wat abt da othrs??

 

[omg]

for question 14
View attachment 12308

therefore h*f + Wa (since it is perpendicular distance between force and pivot)
and the 2Wa part comes from using top of ladder (part resting on wall) as pivot because if distance between pivot and force is 0 then there is no moment

so answer is A = Wa+hf = 2wa

for question 14
View attachment 12308

therefore h*f + Wa (since it is perpendicular distance between force and pivot)
and the 2Wa part comes from using top of ladder (part resting on wall) as pivot because if distance between pivot and force is 0 then there is no moment

so answer is A = Wa+hf = 2wa

y did we change the pivot for takin clockwise and anticlockwise moments??