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You know that the weight is in the middle of the rod.
If you assume the length of the rod to be 1.0 m, and take the wall as the pivot, then you can form an equation:
10.0 * 0.5 = F sin 30 * 1
F = 10.0 N
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You know that the weight is in the middle of the rod.
THANKS XDYou know that the weight is in the middle of the rod.
If you assume the length of the rod to be 1.0 m, and take the wall as the pivot, then you can form an equation:
10.0 * 0.5 = F sin 30 * 1
F = 10.0 N
HELP ME ON THESE QUESTIONS PLS
15 22 32 of n10 variant 12
16 19 34 of J11 variant 12
waiting for quick reply pls with details on this and my previous asked questions on page 38 pls lesco where are u
hELP ME OUT WITH DESE PLS posted on page 38 pls
I have to go somewhere, but when I'll be back I'll try to answer all of your questions. Don't worry dude there's still like 5 days left.leosco1995 plsss mate these questions help will be appreciated ur best explainer pls dude
I = V/r so total r is 2 paralal 100 kohm = 50 kohm and plus one series resistor hence total 150 k ohm hence I=6/150 = 40microAmperes now look at junction current is divided equally coz there is equal resistance in both paths so 40/2 = 20 A (A)i don't know why i'm not getting the correct answer .. It's A
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can anyone explain the concept and provide a solution to this question. ANS: B .
J-11/Var 13
im sry i didnt understand what u really want???nice explanation bro. thanks, but can you elaborate on this '' becuse it is a potential divider..if the thermistor resistance is low the other will be high and so the voltage across it...for the VL''
for q.15 n10 paper 12.leosco1995 plsss mate these questions help will be appreciated ur best explainer pls dude
Go to the thread As physics P1 mcq YEARLY ONLY..and ull find all J 04 explainedASSALAMU ÁLAIKUM
can some one plz explain these sums of paper: s_04_qp_1
23,25,26,28,30,31,33
JAZAK ALLAH
Help, peoplies? :3
im still not clear :/Average speed between XY=40m/12s=10/3 ms^-1 . The average speed occurs at t/2 for uniform acceleration, so at t=6s.
Average speed between YZ=40m/6s=20/3 ms^-1. The average speed occurs at t/2 for uniform acceleration, so at t=3s but for total time it occurs at T=12s(from X to Y) +3s=15s.
So a=Δv/Δt=(20/3-10/3)/(15-6)=10/27=answer A.
AHH! thanks a lot! i didn't notice that before..Go to the thread As physics P1 mcq YEARLY ONLY..and ull find all J 04 explained
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