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AS Physics P1 MCQs Preparation Thread.

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Can someone pls help with these?View attachment 13023View attachment 13024


ans is C for both of the qns

Capricedcapri abdullah ash bloody_mary

ok first find intial speed and final speed so:

intial momentum = final momentum
mu = 2mv

so intial speed is u
and final speed [v] = u/2

intial KE 0.5mu^2
final KE = 0.5 *2m * (0.5u)^2 = 0.25mu^2

final KE/ intial KE = 0.25mu^2 / 0.5mu^2 = 0.5 intial KE so C

----------------------------------------------------------------------------------------

moment = force * perp distance
so resolve the forces
popdfn.png

so 2*cos40 = 0.459 = 0.46 so C
 
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ok first find intial speed and final speed so:

intial momentum = final momentum
mu = 2mv

so intial speed is u
and final speed [v] = u/2

intial KE 0.5mu^2
final KE = 0.5 *2m * (0.5u)^2 = 0.25mu^2

final KE/ intial KE = 0.25mu^2 / 0.5mu^2 = 0.5 intial KE so C

----------------------------------------------------------------------------------------

moment = force * perp distance
so resolve the forces
View attachment 13026

so 2*cos40 = 0.459 = 0.46 so C
thanx so much!:)
 
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In Q . 26
The x axis says time, hence XY represents the time period [the time taken by a wave to complete one wave form]
and the y axis says displacement and since X and Y are in the same position [on the y axis] they'll have the same displacement.
 
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In Q . 26
The x axis says time, hence XY represents the time period [the time taken by a wave to complete one wave form]
and the y axis says displacement and since X and Y are in the same position [on the y axis] they'll have the same displacement.
just 1 question....arent da amplitudes same too?
 
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In Q 31, since the answer is B because a radial field is stronger and the arrows always point away from positive charge to negative charge. Since the particle is positively charged, moving it closer to the field will result in a stronger repulsive force.
 
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