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AS Physics P1 MCQs Preparation Thread.

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thanks alot abcde bt still i did not got the pressure part why u minus .9 frm 1 :S thts where i am stucking
The subtraction is to find the pressure exerted by the liquid column only because you need this piece of information to figure out the height of liquid in the straw.
 
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sure. in the last one about wire.................you knoe that resistence is directly proportional to length and inversely proportional to CSA, hence, since the lenth is same, but you have N number of wires, each has area of AREA/N..hence resistance of individual wores increases, but since there are N wires in paralel when we apply 1/R1 1/R2 + 1/Rn ..............it sums up to be N/RN....the N cancels and take inverse, so resistence is R.....equal
thanks a lot man!!!
 
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no one has solved these two yet, please can you help me with them!!!
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oooohhh u just couldn't imagine how was this question a torture for me...but i finally solved it, see:
first when resolving forces...the forces acting down the inclined plane is mg sin(theta)...to get this theta..u will use the opp/hyp=sin(theta), so sin^-1(3/7)=25.4 is the angle needed...then we have the mass which is 2kg x 9.81 sin(25.4)=8.4N...this is the f0rce down the plane...the resultant force is the 8.4 - the friction force which is 5 = 3.4...then u need to get the acceleration using F=ma...so 3.4/2 = 1.7 ms^-2..and finally using the equation v^2=u^2+2as...so 2 x 1.7 x 7=23.8...v^2=23.8 and so V=4.87 and so the answer is A
Lol you wouldn't believe I did the exact same thing, but evidently made a mistake getting the 8.4N. Anyways now I did it and got it. Thank you so muuch!
 
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i did the same...
2*a*s=v^2-u^2
i got 4.8785 (A) is that correct?
u must hav made some silly mistake...did u get the resultant force 3.4ms^-2?? And acceleration 1.7?
yeah now i did, thnx, and I think its correct, it has to be :D
 
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Hey guys. For O/N/05 question number 34, why is the answer C not B? Since B has the highest gradient in which reciprocal of the gradient represents resistance? Thx in advance :)
 
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