AS Physics P1 MCQs Preparation Thread.

[omg]

Asalaoalikum wr wb

anybody?

IM HAVING PROBLEM IN QS 8 as well
pls anybody helpppppppppppppppppppppppppppppppppppppppp

 

[Silent Hunter]

IM HAVING PROBLEM IN QS 8 as well
pls anybody helpppppppppppppppppppppppppppppppppppppppp

and what about rest ? you know em all?

 

[i love my country]

that is really a good Question me also i need to know why it is D not B can some one explain thanx.....

 

[leosco1995]

ok so if an object is falling in water will upthrust still be lower than drag and weight would be the biggest force. the object is not floating.

Yes.

 

[raamish]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf

in question 12 why is A the asnwer. When an object falls with terminal speed its terminal speed should remain constant. so shouldnt the graph be a straight line showing the acceleration is also 0???

 

[raamish]

Yes.

ok thnx i have another question i just posted please loook at it.

 

[leosco1995]

http://www.xtremepapers.com/community/attachments/9702_w02_qp_1-pdf.11782/
PLEASEEEEEEEEEEEEE can any1 give explanation for q. 35!!!!!!
the ms says the ans is D

If you increase the resistance of the variable resistor, the current decreases. When the current decreases, the p.d. across XY will decrease. Therefore, to balance the galvanometer you need more of the p.d. that is present in the lower circuit, so you shift the contact towards Y.

 

[leosco1995]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_1.pdf

in question 12 why is A the asnwer. When an object falls with terminal speed its terminal speed should remain constant. so shouldnt the graph be a straight line showing the acceleration is also 0???

If you put height at the y-axis and time at the x-axis, then the velocity will be its gradient (height/time). Since the gradient is constant, this means the velocity is constant which is correct.

 

[raamish]

If you put height at the y-axis and time at the x-axis, then the velocity will be its gradient (height/time). Since the gradient is constant, this means the velocity is constant which is correct.

yeh but if the line will be fully staight what will the velocity be then. Will it be constant at that time too?

 

[leosco1995]

yeh but if the line will be fully staight what will the velocity be then. Will it be constant at that time too?

If the line was fully straight the velocity would be zero because the gradient would be zero.

 

[raamish]

ohhhhhhhhhh. i get it now

 

[omg]

and what about rest ? you know em all?

i was so frustated aftr 8 dat i left the ppr and jumpd on another 1!
will do it again aftr sm time

 

[raamish]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf

in 37) why is neutron number not conserved. and from previous questions which asked the same thing it said charge was not conserved. help plz

 

[omg]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf
q.16 and 31 plssssssssssssssssssssssssssssssss

 

[XPFMember]

Waalikumasalaam!
View attachment 12290

JazakAllah khairen..

no wonder...I am coming across this thing first time, though I'm done with my full A level!

that was great help. Glad, came across this before the exam..

JazakAllahu khairen!

 

[omg]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_1.pdf q-14
and
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w08_qp_1.pdf
q-31!
plss helppppppppppppp

 

[Peter Check]

Can anyone help me with these questions??

 

[omg]

ANY1 HAVIN MS FOR SUMMER 2001?????????????????

 

[USMAN Sheikh]

Nov 2010 P11 Q5

3000 rev/min

= 50 rev/sec

time period for one rev = 0.02s

For the wave to appear on a 10 cm screen, 0.02/10 = 0.002s.

Then you will divide by 2 for one pulse to appear = 0.001s or 10 ms/cm.

not clear how 0.001 = 10ms :S

 

[bloody_mary]

ANY1 HAVIN MS FOR SUMMER 2001?????????????????

here you go love