AS Physics P1 MCQs Preparation Thread.

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leosco1995

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MysteRyGiRl said:
cz apparently we havent solved those :/
btw can u help out? when do we use 1/2 kx^2 and when do we use 1/2 fx?
Click to expand...
They are the same thing, F is just replaced with kx in the first equation.. I think it just depends on what data is given to you, no?
 
Soldier313

Soldier313

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00tanveer said:
At O a maximum is observed. Now, u r moving the detector up to X. A MINIMUM is observed at X since the question says no signal is detected here. So what do we know? At minima, the path difference of two waves falling on a point is (n+ 1/2)*lambda, where n is the number of orders of dark fringes. So at X, n=0 so path difference is 1/2*lambda. Hope it helped, dudette (I believe ;) )
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owh ryt thanx a lot!.......and yeah you remember well, dudette..... it is:p
 
Soldier313

Soldier313

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N.M said:
in elastic collisions kinetic energy is always conserved
so, the sum of velocity b4 collision must equal that after collision
that means
u1+v1=u2+v2
but at the same time you need to keep a reference direction
lets say towards the right is positive
so the eqn for this case will be ux+(-vx)=(-uy) + vy
now you can simply rearrange to get the correct answer that is A

hope its clear now
Click to expand...
i have a qn related to this....shouldn't the eqn therefore be:
ux - uy = vy - ux
since total velocity BEFORE collision has to equal total velocity AFTER collision:unsure:
 
applepie1996

applepie1996

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Soldier313 said:
reposting my qn...urgent assistance required....thanx!
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Relative speed of approach = relative speed of departure
Ua - Ub = Vb - Va

then according to da directions v put da signs lyk:
(+ Ua) - (- Ub) = (+ Vb) - (+ Va)

so finally v get:
Ua + Ub = Vb - Va
i think this correct i dunno
 
N.M

N.M

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Soldier313 said:
i have a qn related to this....shouldn't the eqn therefore be:
ux - uy = vy - ux
since total velocity BEFORE collision has to equal total velocity AFTER collision:unsure:
Click to expand...

i sorry i didnt get the eqn that u have mentioned
the equation that i have mentioned is correct and u can simply rearrange the eqn that i wrote in the post n the final answer will be
ux+uy=vx+vy
 
biba

biba

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i hav done all the papers from j/02 till nov/11 for physix.....my average marks are 35...
is that good enough? :cautious:
 
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