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they don't stick togetherooops i didn't see that they stick togther so one v will be negative but that is the base forumla you should use
hope it helped
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they don't stick togetherooops i didn't see that they stick togther so one v will be negative but that is the base forumla you should use
hope it helped
Which paper?
sorryq.19 of wich year?
u dont need k here.
0.5FE = 0.5 * 0.40 * 2
hey will u look at q.7.0.5FE = 0.5 * 0.40 * 2
= 0.40 J
k = 2/0.40 = 5
1/2 * 5 * 0.40 * 0.40 = 0.40 J
I used both formulas. Both gave the same answer. But I recommend using the one which requires less working (over here 1/2 * Fe).
aah why did u divide .40 by 2??0.5FE = 0.5 * 0.40 * 2
= 0.40 J
k = 2/0.40 = 5
1/2 * 5 * 0.40 * 0.40 = 0.40 J
I used both formulas. Both gave the same answer. But I recommend using the one which requires less working (over here 1/2 * Fe).
because 2N is the force!aah why did u divide .40 by 2??
its charge to mass ratio. and dats part of A2!!!
okayomg can i explain q15 tomorrow
could u help me out plz...hv posted my questions in da previous post and also plz explain where u said 2N is da force...okay
for q.11,
Q14)1/2mu^2=mghlesco thanks alot man u r doing a great job few more questions for u kindly solve them pls
q 14 and 36 of june 11 variant 11
q 26 28 36 of november 11 variant 11
for q.11,
first u can find the mass using F=mg
20N=m10
so mass=2kg
now the net force in (10-4=6N)
so, 6=2 x a
a=3! hence C!!
im nt sureeee abt 13 :/thnx !! umm 13?
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