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AS Physics P1 MCQs Preparation Thread.

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0.5FE = 0.5 * 0.40 * 2
= 0.40 J

k = 2/0.40 = 5

1/2 * 5 * 0.40 * 0.40 = 0.40 J

I used both formulas. Both gave the same answer. But I recommend using the one which requires less working (over here 1/2 * Fe).
hey will u look at q.7.
as the ball is thrown horizontally, it will follow a parabolic path ryt? so shouldnt the horizontal component ov velocity remain constant??
 

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0.5FE = 0.5 * 0.40 * 2
= 0.40 J

k = 2/0.40 = 5

1/2 * 5 * 0.40 * 0.40 = 0.40 J

I used both formulas. Both gave the same answer. But I recommend using the one which requires less working (over here 1/2 * Fe).
aah why did u divide .40 by 2??
 
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red fonts question on page 41 and on page 38 (normal fonts )pls any one repond to that plsssss andy one plsss
 
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lesco thanks alot man :) u r doing a great job few more questions for u :) kindly solve them pls :)
q 14 and 36 of june 11 variant 11
q 26 28 36 of november 11 variant 11 :)
Q14)1/2mu^2=mgh
m gets cancelled so u^2=2gh take 2g as k which is constant
so h is divide by 2 so u^2/root of 2
so v^2=u^2/root2
so 1/root2
dunt noe if its correct just did it
 
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