AS Physics P1 MCQs Preparation Thread.

omg

Messages
626
Reaction score
3,628
Points
253
0.5FE = 0.5 * 0.40 * 2
= 0.40 J

k = 2/0.40 = 5

1/2 * 5 * 0.40 * 0.40 = 0.40 J

I used both formulas. Both gave the same answer. But I recommend using the one which requires less working (over here 1/2 * Fe).
hey will u look at q.7.
as the ball is thrown horizontally, it will follow a parabolic path ryt? so shouldnt the horizontal component ov velocity remain constant??
 

Attachments

  • 9702_w10_qp_11.pdf
    222.5 KB · Views: 0
Messages
3,063
Reaction score
1,831
Points
173
0.5FE = 0.5 * 0.40 * 2
= 0.40 J

k = 2/0.40 = 5

1/2 * 5 * 0.40 * 0.40 = 0.40 J

I used both formulas. Both gave the same answer. But I recommend using the one which requires less working (over here 1/2 * Fe).
aah why did u divide .40 by 2??
 
Messages
120
Reaction score
17
Points
28
red fonts question on page 41 and on page 38 (normal fonts )pls any one repond to that plsssss andy one plsss
 
Messages
1,601
Reaction score
553
Points
123
lesco thanks alot man :) u r doing a great job few more questions for u :) kindly solve them pls :)
q 14 and 36 of june 11 variant 11
q 26 28 36 of november 11 variant 11 :)
Q14)1/2mu^2=mgh
m gets cancelled so u^2=2gh take 2g as k which is constant
so h is divide by 2 so u^2/root of 2
so v^2=u^2/root2
so 1/root2
dunt noe if its correct just did it
 
Top