AS Physics P1 MCQs Preparation Thread.

[bloody_mary]

hmm the answer is B, actually

you sure you have the right mark scheme infront of you?

 

[Wanzi21]

how to do this???/

 

[Wanzi21]

you sure you have the right mark scheme infront of you?

yes im really sure the correct answer is B :/

 

[bloody_mary]

heyy can some1 help me with nov.10 1st variant q.34???????????????and in da 2nd variant Q 27,34 and in 31 why cant the answer be B ??ty

Q34
lets draw a diagram first

now the resistance in each wire is 0.005 per meter so resistance in 1 wire is 800 * 0.005=4
so both wires have resistance 8

we can redraw the diagram and place the resistanc of the wires as 1 single resistor component


the resistance of the relay is 16/0.6= 26.6667

using equation v/E = R1/R1 + R2

so 16/E = 26.667/26.667 + 8 solve to get E is 20.8

Q27 i can't do

Q34 answer is B because i higher resistivity for same length and area means more resistance it can't be C because it doesn't fall that sharply

Q31 answer is A because when there is a current the electrons flow in the wire when there aren't they move absurdly as they orbit protons (if you took chemistry then remember metallic structre)

and next time post paper + ms

 

[bloody_mary]

yes im really sure the correct answer is B :/

paper and ms please

 

[MysteRyGiRl]

Q34
lets draw a diagram first View attachment 12820

now the resistance in each wire is 0.005 per meter so resistance in 1 wire is 800 * 0.005=4
so both wires have resistance 8

we can redraw the diagram and place the resistanc of the wires as 1 single resistor component
View attachment 12821

the resistance of the relay is 16/0.6= 26.6667

using equation v/E = R1/R1 + R2

so 16/E = 26.667/26.667 + 8 solve to get E is 20.8

Q27 i can't do

Q34 answer is B because i higher resistivity for same length and area means more resistance it can't be C because it doesn't fall that sharply

Q31 answer is A because when there is a current the electrons flow in the wire when there aren't they move absurdly as they orbit protons (if you took chemistry then remember metallic structre)

and next time post paper + ms

which ppr is dis?? :S

paper and ms please

its da same question about da frequency thing...

 

[umarashraf]

Best of luck for the paper to you all

 

[hm12]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf
please explain question 9 why is the answer C and not D?

please some one help me with this i am posting this question the 3RD time please help

 

[bloody_mary]

which ppr is dis?? :S

its da same question about da frequency thing...

from xxxtoughxxx "heyy can some1 help me with nov.10 1st variant q.34???????????????and in da 2nd variant Q 27,34 and in 31 why cant the answer be B ??ty"

and what are you saying about the frequency thing?

 

[umarashraf]

initial momentum of the ball is 2mv before collision... if collision was perfectly elastic one, all the momentum would have been gained by the ball... and this would have made the change in the momentum equal to 4mv.. 2mv-(-2mv)... now it is given that collision is inelastic, it wil losse some of its momentum to the wall.. so now change in momentum will be less than 4mv but cant be less than the initial momentum... so the answer is C.. i think you cannot verify the answer by the calculations...

 

[MysteRyGiRl]

from xxxtoughxxx "heyy can some1 help me with nov.10 1st variant q.34???????????????and in da 2nd variant Q 27,34 and in 31 why cant the answer be B ??ty"

and what are you saying about the frequency thing?

oh ok
da question on da previous page i think...

 

[umarashraf]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf
please explain question 9 why is the answer C and not D?

please some one help me with this i am posting this question the 3RD time please help

initial momentum of the ball is 2mv before collision... if collision was perfectly elastic one, all the momentum would have been gained by the ball... and this would have made the change in the momentum equal to 4mv.. 2mv-(-2mv)... now it is given that collision is inelastic, it wil losse some of its momentum to the wall.. so now change in momentum will be less than 4mv but cant be less than the initial momentum... so the answer is C.. i think you cannot verify the answer by the calculations...

 

[bloody_mary]

Question 14 pleaseee

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_qp_11.pdf
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_ms_11.pdf

 

[bloody_mary]

oh ok
da question on da previous page i think...

idk someone posted a screen shot

 

[lavanyamane]

yup that is because it is in mechanics

Ahh! Thank you for the help

 

[bloody_mary]

Ahh! Thank you for the help

welcome love

 

[MysteRyGiRl]

idk someone posted a screen shot

yea dat question..

 

[applepie1996]

initial momentum of the ball is 2mv before collision... if collision was perfectly elastic one, all the momentum would have been gained by the ball... and this would have made the change in the momentum equal to 4mv.. 2mv-(-2mv)... now it is given that collision is inelastic, it wil losse some of its momentum to the wall.. so now change in momentum will be less than 4mv but cant be less than the initial momentum... so the answer is C.. i think you cannot verify the answer by the calculations...

yup dats wat i thought 2

 

[lavanyamane]

Question 14 pleaseee

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_11.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_ms_11.pdf

Initial KE = 2 * final KE ( because the ball rebounds to half its original height)
So, 1/2*m*u^2 = 2*1/2*m*v^2
1/2*m*u^2 = m*v^2
Rearrange in the form v/u and you get 1/(root) 2

 

[applepie1996]

View attachment 12706View attachment 12707

Can i get the solution to these two questions?

ANS:
15 B
31 C

Over here Fs = 4 J
So 2F * 2s = 16 J

So the change is now 16 J

So final = initial + change
= 4 + 16 = 20 J