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yes, thank you.so is it ok now..???
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yes, thank you.so is it ok now..???
oh ok sorrynope the answer is 10 GHz
Hi,Need help with a few question. If someone cud help, please.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_12.pdf
Q 8, 25, and 34
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_11.pdf
Q 27 and 33.
sorry for the late reply... the working i showed first is wrong, I'm sorry if i made you waste your time (found out looking at http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_er.pdf pages 5 and 6)
This is the correct working added a bit more detail, and also d=1/N you can look at this link http://www.s-cool.co.uk/a-level/physics/diffraction/revise-it/diffraction-from-a-diffraction-grating. sorry again
PE = KE + WD? What is this formula? :S Thank you so much!
hi.. can you help me with this ^^View attachment 12742
sorry? im stuck on this one, cud u please write the solution?question 8, first you got to find the velocity till 30 meters. then use that initial velocity to find acceleration for last 10 meters.
hmm the answer is B, actuallyfrequency = 1/T
so T is 1/50 which is 0.02s which is the same as 20ms so answer is D
oh sorry i mixed it up with some other mcq, didn't read all..sorry? im stuck on this one, cud u please write the solution?
no problemoh ok sorry
hahaha i wasn't showing off! i just needed some opinions u knowobviously they r good! show off!
mission successful, u took it serious, i know i m just having fun.hahaha i wasn't showing off! i just needed some opinions u know
cuz i sucked in physix my p2 went bad!!!!!
hahahaha yeah rightmission successful, u took it serious, i know i m just having fun.
bdw i didn't sucked that bad in p2. i don't like to ponder over past. shuuu 4get dat ppr. mcqs on my mind now.
hv a look at it guys
it sure didI believe the answer is C because as the kinetic energy increases, the change in speed required to do this increase actually decreases. This is due to kinetic energy being proportional to the square of the velocity. Let me explain...
Increase in K.E. ----> Increase in speed
1-->10 1-->3.16 (change 2.16)
10-->20 3.16-->4.47 (change 1.31)
20-->30 4.47-->5.48 (change 1.01)
In this example, even though there is a constant increase in K.E., the change in velocity decreases as the K.E. increases.
Hope that helped. : )
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