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AS Physics P1 MCQs Preparation Thread.

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Hi,
question 8, first you got to find the velocity till 30 meters. then use that initial velocity to find acceleration for last 10 meters.

34) the resistivity increases and voltage increases as well (directly proportional) so gradient has to go more steep as we move along..

2nd ppr: 27th its zero cause force is centripetal, towards the center and the distance moved is not in the direction of force.

33) each resistor originally will share equal power as they have equal resistance (forget the circuit combination for a while)

now remember again: the two resistors Q and R are connected in parallel. so 1/4 + 1/4 = 1/P, this will give us 2W
 
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sorry for the late reply... the working i showed first is wrong, I'm sorry if i made you waste your time (found out looking at http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_er.pdf pages 5 and 6)
This is the correct working added a bit more detail, and also d=1/N you can look at this link http://www.s-cool.co.uk/a-level/physics/diffraction/revise-it/diffraction-from-a-diffraction-grating. sorry again :(

it's ok thanks though :D
 

omg

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hv a look at it guys
 

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sorry? im stuck on this one, cud u please write the solution?
oh sorry i mixed it up with some other mcq, didn't read all..

s= ut + 1/2 at ^2 , total distance = 80 m , u will be zero, time is 18 seconds,

80= 1/2 into a into 324 , 80/162 = .49 ms^-2
 
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hahaha i wasn't showing off! i just needed some opinions u know :p
cuz i sucked in physix my p2 went bad!!!!!
mission successful, u took it serious, i know i m just having fun. :)
bdw i didn't sucked that bad in p2. i don't like to ponder over past. shuuu 4get dat ppr. mcqs on my mind now. :)
 
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hv a look at it guys

I believe the answer is C because as the kinetic energy increases, the change in speed required to do this increase actually decreases. This is due to kinetic energy being proportional to the square of the velocity. Let me explain...

Increase in K.E. ----> Increase in speed
1-->10 1-->3.16 (change 2.16)
10-->20 3.16-->4.47 (change 1.31)
20-->30 4.47-->5.48 (change 1.01)

In this example, even though there is a constant increase in K.E., the change in velocity decreases as the K.E. increases.

Hope that helped. : )
 

omg

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I believe the answer is C because as the kinetic energy increases, the change in speed required to do this increase actually decreases. This is due to kinetic energy being proportional to the square of the velocity. Let me explain...

Increase in K.E. ----> Increase in speed
1-->10 1-->3.16 (change 2.16)
10-->20 3.16-->4.47 (change 1.31)
20-->30 4.47-->5.48 (change 1.01)

In this example, even though there is a constant increase in K.E., the change in velocity decreases as the K.E. increases.

Hope that helped. : )
it sure did :D
THANKS a lot!
=D
 
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