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variant 2,ques 29which variant?
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variant 2,ques 29which variant?
owh okay thanxthe size of the arrows shows the magnitude of the force..W have the smallest arrow..then H is a bit larger than W and t is the greatest so C
please solve this and explain how do we solve wheatstone bridge circuits for effective resistance and current on each component?go to page 79 of this thread and ull find me explaining the whole NOv 2011 P1 variant 1 and 2..and ull find that i explained this question with details that will help u alot
m/j/09/01
mcq no. 2 ,10,11 n 14
plzzzzzzzzzzzzzzzz anyone !
Listen guys, what is conserved in a nuclear reaction and what isn't?
PLEASE HELP I"M REALLY CONFUSED
For Q.11:why did you use the second mass equal to 20 kg whereas in the question it says that one mass of 20 kg....collides with a mass of 12 kg??plzz helpgo to page 79 of this thread and ull find me explaining the whole NOv 2011 P1 variant 1 and 2..and ull find that i explained this question with details that will help u alot
Please, someone answer this. I'd be reallyy grateful.
View attachment 12955
the answers are A and D respectively.
A trolley runs from P to QAt P, the kinetic energy of the trolley is 5kJ. Between P and Q, the work the trolley does against
friction is 10kJ.
What is the kinetic energy of the trolley at Q?
A 35kJ B 45kJ C 55kJ D 65kJ
plzzz help guys!
yesanswer is B right?
btw u missed part of the question abt PE of Q which is less than P by 50kj
The formula for use here is X = lambda x distance between screen and slits / distance between slits. Here, X stands for the distance between 2 CONSECUTIVE dark OR bright fringes. So for example if you take the distance between 2 dark fringes from the second diagram, it will be around 3mm ( 3x10^-3 m ). Substituting all these values into the formula you'll get:variant 2,ques 29
FOR Q8)Please, someone answer this. I'd be reallyy grateful.
View attachment 12955
the answers are A and D respectively.
But its uniform acceleration, and the formula V=d/t, isn't this for costt. velocity?FOR Q8)
Calculate individual velocities .
between X & Y (40/12)=3.33 ms^-1 AND from Y to Z (40/6)=6.67 ms^-1
Next calculate the average time taken (12+6)/2=9 sec... find acc. It comes like (6.67-3.33)/9 = 0.37 ms^-2
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