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They asked about each pulse, so u see it each pulse takes 2 squares--> 2 cm and since timebase setting is 1, so 1*2=2 microseconds
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AS Physics P1 MCQs Preparation Thread.
- Thread starter mujtabashahnawaz
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They asked about each pulse, so u see it each pulse takes 2 squares--> 2 cm and since timebase setting is 1, so 1*2=2 microseconds
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They asked about each pulse, so u see it each pulse takes 2 squares--> 2 cm and since timebase setting is 1, so 1*2=2 microseconds
no. 33 & 34 http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w05_qp_1.pdf
no. 17 http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w06_qp_1.pdf
help plz
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33--> as simple as that! strain increases means length increases increasing resistance as well.. no need to even think about the cross sectional area..
34--> Sorry I am not sure about this. h4rriet please help!
17--> they said 93% is heat while 7% is light... so 93+7=100... answer is simple 7% ((7/100)*100) - I guess, thats how i understood it..
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33--> as simple as that! strain increases means length increases increasing resistance as well.. no need to even think about the cross sectional area..
34--> Sorry I am not sure about this. h4rriet please help!
17--> they said 93% is heat while 7% is light... so 93+7=100... answer is simple 7% ((7/100)*100) - I guess, thats how i understood it..
he is the superman of the xtremepaper
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U have to find R first. R=V/Ihe is the superman of the xtremepaper
At point A B and D, ratio of V:I will be higher as V is more than I so ratio will be higher than 1. At C they are almost equal so ratio will almost be 1 so its the smallest value of R
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u dont have to find it quantitatively. just take ratios. Ratio of V:I is smallest for C so R is smallestno datas given . how to find r ? >
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http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_12.pdf can someone plz help with q8 and 22.thanks!
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mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
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Q .. if ratio of power of x / power of y is 2 ...mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
what will be the ratio of resistance of x /resistance of y ...
ans is 4 .. but i couldnt get the hint using p=I^2R
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is there a short note regarding all kinds of momentum ?, mainly about collisions which is rather confusing for me it would be gr8 if anyone could help
it would be gr8 if anyone could help
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mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
thanks alot!!!
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http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w09_qp_12.pdf
q4,8,9,12,13,18,20,21
this paper was a tough one please help me with these someone?
q4,8,9,12,13,18,20,21
this paper was a tough one please help me with these someone?
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- Messages
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I need some help with a few questions.. please explain the solution.
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_11.pdf
Qn no. 4, 8, 13, 31
The questions I asked look pretty simple.. but I just can't think of what to do.
I'll appreciate your help..
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_11.pdf
Qn no. 4, 8, 13, 31
The questions I asked look pretty simple.. but I just can't think of what to do.
I'll appreciate your help..
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can u plz give me the link to this qts .....
its no . 29 >>>http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w07_qp_1.pdf
btw help me with no . 17 also >
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_1.pdfthanks
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mcq22...first calculate density =mass/volume, then use density= cuberoot volume to calculate the distance u will get C...
mcq 8...using v1= a*t1
v2 = a*t2
then use 2as= (v2)^2 - (v1)^2
or else use this method , in vertical case lyk this one u need to knw that s= 1/2 at^2 is used...
put values in this eq nd u vl get 2h/(t2^2 - t1^2)
hope u get these...
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_11.pdf sorry for bothering u agian plz tell how to do q36.
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A double slit experiment, using light of wavelength 600nm, results in fringes being produced on a
screen. The fringe separation is found to be 1.0mm.
When the distance between the double slits and the viewing screen is increased by 2.0 m, the
fringe separation increases to 3.0mm.
What is the separation of the double slits producing the fringes?
pls can anyone help?
9702_w10_qp_12.pdf Q27