Biology; Chemistry; Physics: Post your doubts here!

[Saad Mughal]

I think we use the formulae W=F*d, then use the value of W in the formulae K.E=1/2mv2 to find the speed maybe..

I tried. Not getting an answer that is in the options..
I think there is a reason for the given 30 deg. angle.

 

[usama321]

Koi BAAP ka DADA hai to explain this MCQ..
Energy, Work and Power MCQ 50

http://books.google.com.pk/books?id...=gbs_selected_pages&cad=3#v=onepage&q&f=false

lol at baap ka dada

 

[ijlalm]

Agar Yeh aagaya CIE main!!!

 

[Saad Mughal]

lol at baap ka dada

He's just going to keep doing that. Eh, ijlalm?
It started with BAAP then BAAP ka DADA, next time it's going to be BAAP ka DADA ka PER DADA.

 

[Saad Mughal]

Agar Yeh aagaya CIE main!!!

Yaar darao mat, agar aese sawal anay lg gaye tou phir tou gaye hum.

 

[ijlalm]

He's just going to keep doing that. Eh, ijlalm?
It started with BAAP then BAAP ka DADA, next time it's going to be BAAP ka DADA ka PER DADA.

Maybe!

 

[Saad Mughal]

Maybe!

 

[asma tareen]

what if we apply any of the trignometrical ratios to find the distance and thn calculate speed

 

[usama321]

what if we apply any of the trignometrical ratios to find the distance and thn calculate speed

i was actually applying sin 30, and get mgh.....lets see

 

[Saad Mughal]

what if we apply any of the trignometrical ratios to find the distance and thn calculate speed

You need at least one distance for that.

 

[usama321]

Maybe!

is the answer A?

 

[asma tareen]

You need at least one distance for that.

we have 10 km dont we???

 

[usama321]

You need at least one distance for that.

awwwwwwwwww, lol i was thinking by 10cm in the end it meant that the mass had travelled 10 cm that was how i was trying sin 30 * 10 = h

 

[usama321]

the question is a bit vague too, coupled with the difficulty. Whats the purpose of the 10cm arrow below 5 kg mass, and were they balanced at the start?

 

[asma tareen]

look the 5 kg box travelled 10 cm so this can be the perpendicular distance

 

[Saad Mughal]

awwwwwwwwww, lol i was thinking by 10cm in the end it meant that the mass had travelled 10 cm that was how i was trying sin 30 * 10 = h

I've tried some weird things, I'm not getting an answer.
I'll just ask my teacher, I guess.

 

[usama321]

and if the two were balanced at start, i tried 5*10 = 1*x making the weight of the 1 kg box 5oN

 

[Saad Mughal]

look the 5 kg box travelled 10 cm so this can be the perpendicular distance

They've already told us that the 1 kg box moves 10 cm, if you're applying trig. ratios with the 10 cm information, you'd get hypotenuse = perpendicular distance = 10 cm!

 

[Saad Mughal]

and if the two were balanced at start, i tried 5*10 = 1*x making the weight of the 1 kg box 5oN

If weight of 1 kg mass was 50 N (which means that the gravitational field was 50 N/kg) the 5 kg mass would have a weight of 250 N!

 

[asma tareen]

hmm look 5 kg will apply 5 times more force than 1 kg right???