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calcium is group 2?gp 1 carbonates are soluble dude
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calcium is group 2?gp 1 carbonates are soluble dude
oh well....um it goes like hydroxdes r most soluble(mostly the only form aqueous solutions)...then comes oxides n then carbonates....if v comapre these three on anion side
and Ca is in group 2
Carbonate - all insoluble except Group 1 and Ammonium salts.Saad Mughal though i have never seen it anywhere in any book, i just searched google and saw that Calcium carbonate is insoluble. I thought only group one and ammonium carbonates were insoluble?
OMG, i have reversed it up. thanks for pointing that out, i thought group 1 and ammonium carbonates are insoluble.. thanksu wrote its insoluble
ohk? thtz new?here it says hydroxides are mostly insoluble?
https://www.xtremepapers.com/commun...istry-soluble-and-insoluble-substances.24846/
Do topical Acids and Bases questions, they help in reinforcing your memory of the solubility of salts.OMG, i have reversed it up. thanks for pointing that out, i thought group 1 and ammonium carbonates are insoluble.. thanks
Carbonate - all insoluble except Group 1 and Ammonium salts.
Hydroxides - all insoluble except Group 1, Group 2 (Ca, Ba) and Ammonium salts.
Nitrates - all soluble.
Sulphates - all soluble except BaSO4, PbSO4, CaSO4.
Halides (Cl,Br,I) - all soluble except Lead Halide, Silver Halide.
No, I've learnt things from different sources (I know about oxides too but they are not part of the syllabus). The book Fundamental Chemistry (in my opinion) is one of the best books to cover the chemistry syllabus. It has details of everything relevant only to the syllabus.saad do u take tuitions from sir rizwan khan? b/c he made us write in the same pattern
:O
ohhNo, I've learnt things from different sources (I know about oxides too but they are not part of the syllabus). The book Fundamental Chemistry (in my opinion) is one of the best books to cover the chemistry syllabus. It has details of everything relevant only to the syllabus.
And yeah, I know Sir Rizwan Khan teaches in the same way, I came across this in a thread and one of my friends takes his tuition so he told me about his teaching pattern.
Here you go.Can anyone list all the transformation matrices? (including shear and stretch)
(a)(ii) I'm not sure of whether I'm using the correct method, but for thermometers the general formula is (Xy-X0/X100-X0) * 100.http://papers.xtremepapers.com/CIE/Cambridge International O Level/Physics (5054)/5054_w12_qp_21.pdfquestion 2 part a sub part 2 and part b! help me please!
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Physics (5054)/5054_w12_qp_21.pdfquestion 2 part a sub part 2 and part b! help me please!
thnkeeew(a)(ii) I'm not sure of whether I'm using the correct method, but for thermometers the general formula is (Xy-X0/X100-X0) * 100.
In this thermocouple, the varying quantity is the voltage and the division b/w the two junctions (given) is 50 deg., so,
Initial voltage = 6.2 mV, Final voltage 6.8 mV,
The given information is that the two junctions produce a difference of 50 deg. when the voltage changes from 6.2 mV to 7.7 mV.
Just put this in the equation,
6.8-6.2/7.7-6.2 * 50 = 20 deg.
This is the temperature change, add it to the initial temperature (750) to get the final temperature = 770 deg.
(b) The liquid in glass thermometer is inappropriate since the liquid is most likely to boil off at such a high temperature.
Hope that helps.
thankiees!!!For a change of 50 C, there was an increase in voltage of 1.5. So, if the increase had been 1, 50/1.5. now, for an increase of .6V (thats the question) we will do 50/1.5*.6 = 20. Add this 20 to 750 and you got your answer (by the way this here is the use of linear output, as there is a constant change of 50/1.5 degree C for every one unit voltage )
ohh i got ithttp://papers.xtremepapers.com/CIE/Cambridge International O Level/Physics (5054)/5054_w12_qp_21.pdf question 8 part b sub part 2. ammeter reading increases because current i inversely proportional to resistance, so when resistance decreases, the current increases. but what about the voltmeter reading??
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